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last page variable


justAnoob

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having trouble find last page for pagination. if i'm on the last page, i would like it to not show the "Next" button.

Here is the echo for the "next button"

if (!(($startrow / $display) == $pages) && $pages != 1)
{ 
         $next = $startrow + $display; 
         echo '<a href="testing2.php?startrow=' . $next . '">Next</a> '; 
}

$count is my total number of rows from mysql  and

$display is the number of pics to be displayed on each page  and

this gets my total number of pages

pages = intval($count / $display);

This seems so simple, but I cannot get it to work.

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Nothing yet

This is what I got

<?php
if (floor($startrow/$display) < $pages && $pages != 1)
{
echo '';
}
else
{ 
       $next = $startrow + $display; 
       echo '<a href="testing2.php?startrow=' . $next . '">Next</a> '; 
}
?>

This is my $startrow var below

$startrow = $_GET['startrow'] ? $_GET['startrow'] : 0;

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can't get it to work that way. The example below works, but I'm looking to change the display amount to 10, But I can't figure out what to change the if statement to so it will still work correctyly.

<?php
$startrow = $_GET['startrow'] ? $_GET['startrow'] : 0;

$pages = intval($count / $display); 

if ($count % $display)
{ 
    $pages++; 
} 

if ($pages > 1)
{ 
    for ($i=1; $i <= $pages; $i++)
{ 
    	$next = $display * ($i - 1); 
    	echo '<a href="testing2.php?startrow=' . $next . '" class="active" >  ' . $i . '  </a> ';
}

} 

$last = ceil($count / $display); 

if(! (($last + 6) < $startrow ) && $pages != 1)
{
$next = $startrow + $display;
echo '<a href="testing2.php?startrow=' . $next . '" class="active" >Next >>></a> ';    
}
else
{
echo '<span class="inactive">Next >>></span>';
}
?>

Most of the code is from an example online that I found.

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