testing for file's existence

[Ninjakreborn]

I have 30 file's I allow to be uploaded at a time on one project
<label for="file1">Image 1</label>
<input name="file1" id="file1" type="file" /><br />
that is what each one looks like just with a different number
on the other page I am testing for the upload with
if (isset($_POST['file1'])) {
// file was uploaded
}

[gmwebs]

I am not sure I understand the question...?

[trq]

Read the link in my signiture. Seriously.

[Ninjakreborn]

I have a form with 31 potential file uploads.  I want to test each file to see if they tried to upload a file, if they did, then I go ahead and check if the file exists, and rename it, or whatever else.
I only want ot try to work with file's however they they attempted to upload.  The one's they left blank I want to ignore, but that didn't work, like if it was a text field, that would check to see if it was field out, if it was then I can validate it, it's not working with file uploads.

Sorry it was so unclear at first.  trying to deal with 30 file uploads at once has got me feeling a little dizzy, and my head is spinning.  I went from a few huge things today, over to trying to do mass file uploads.  It's been a hell of a day, that's why I sound out of it, sorry about that.

[gmwebs]

One way is to post an array of files, and then iterate through the array with a while loop, moving and renaming each file until there aren't anymore.

[roopurt18]

Anything uploaded will appear in $_FILES.

[Ninjakreborn]

How do you just test for an upload attempt.
If you have a input field, it's it's just
<input name="hello" id="hello" type="text"  />
then you can just go
if (isset($_POST['hello'])) {
// field was filled out.
}
I need to get the same type of affect with file upload's, but it doesn't work like this, how do I test for it?

[gmwebs]

In your form, for each upload field you have, name it like this...

[code]<input name='upload_file[]' type='file' >[/code]

Then in the script you are POSTing to, the files can be accessed by [code=php:0]$_FILES['0'][/code] through to [code=php:0]$_FILES['29'][/code].

[Ninjakreborn]

I know how to access the file's specifically.  I am just wondering hwo to do a test for the file.
If they didn't attempt to upload one it doesn't show, if they did, then it tries to work with it.
will this work
if (is_uploaded_file($_FILES['file1'])) {
// validate file
// rename file
// move file
}
then if it didn't then it just ignores that block of code?

[gmwebs]

The $_FILES array will *only* contain the files that were uploaded, so if your user only used 5 fields, then there would only be 5 files to work with in the $_FILES array (0 through to 4) so you would not need to test for their existance.

[Ninjakreborn]

The reason I am wondering about doing it the long way.
I want to get solid with working on file's I don't work on them often, I am still weak at them.  I want to get a lot better at individually working on seperate file's then later i will start doing it with an array.  Right now I just want to 1 at a time test to see if each file was uploaded.
Like this

if (they attempted to upload file1) {
// validate file, rename file, move file
}else {
// ignore existence
}
if (they attempted to upload file2) {
// validate file, rename file, move file
}else {
// ignore it
}
if (they attempted to upload file3 ) {
// validate file, rename file, move file
}else {
//ignore it
}
and so forth for each of the 31 files.  This will get me better at them individually.  THen later I can go in and learn how to do them with array's to make it 4 time's faster.

[gmwebs]

Well... whether you upload 1 or 300 files, they are still in the $_FILES array. If you want to work through each one separately writing 100 lines of code when one while loop will do it, then be my guest  ;D

[code]
<?php

// Fetch the file array for file1
$file1 = $_FILES['file1'];

// Count the number of files uploaded
if (count($file1) > 0) {
//do your code to move and rename file1
}

//repeat many times over... ;)
?>
[/code]

[Ninjakreborn]

I am not explaning it right.  How do I test to see if they put something in the little box where the file is.
<input name="file1" type="file" />
there is a blank line there, if they upload a file it fills it with the filename of there server, if not it sends it blank, I just want to check to see if they clicked upload, and picked a file, for that specific one before hitting submit.

[roopurt18]

Every form field of the following type:
<input type="file" name="some_name"/>

creates a corresponding entry in the $_FILES array.  You check if the user put something into the field by checking for the corresponding entry in $_FILES.

[gmwebs]

Each file upload field on your form has a name.

[code]
<input name='file1' type='file' />
<input name='file2' type='file' />
<input name='file3' type='file' />
<input name='file4' type='file' />
<input type="submit" name="submit" value="upload" />
[/code]

On your processing script, there will be a $_FILES array for each field.

[code=php:0]$_FILES['file1][/code]

[code=php:0]$_FILES['file2][/code]

[code=php:0]$_FILES['file3][/code]

[code=php:0]$_FILES['file4][/code]

You would then test each field to see if it contains any values in the array, and if it does, perform your move and rename functions.

[code]
<?php

// Fetch the file array for file1
$file1 = $_FILES['file1'];

// Fetch the file array for file2
$file2 = $_FILES['file2'];

// Fetch the file array for file3
$file3 = $_FILES['file3'];

// Fetch the file array for file4
$file4 = $_FILES['file4'];

// Check file1
if (count($file1) > 0) {
//do your code to move and rename file1
}

// Check file2
if (count($file2) > 0) {
//do your code to move and rename file1
}

// Check file3
if (count($file3) > 0) {
//do your code to move and rename file1
}

// Check file4
if (count($file4) > 0) {
//do your code to move and rename file1
}

?>
[/code]

[akitchin]

the count method will not work, as the $_FILES array is sent whether the files are empty or not.

files uploaded are located in the $_FILES array, NOT IN THE $_POST array.  to check if a file has been selected or uploaded or not, all you have to do is check the filename:

[code]if (empty($_FILES['input_name']['name']))
{
  no file uploaded for input_name
}[/code]

refine your question if this doesn't answer it.

[gmwebs]

Yep, Akitchin you are right... Thanks for putting us straight... I have included a script which will test exactly what you are saying...

[code]
<?php

// Fetch the file array for file1
$file1 = $_FILES['file1'];

// Fetch the file array for file2
$file2 = $_FILES['file2'];

// Fetch the file array for file3
$file3 = $_FILES['file3'];

// Fetch the file array for file4
$file4 = $_FILES['file4'];

// Check file1
if (!empty($file1['name'])) {
//do your code to move and rename file1
echo "File1 Exists | ";
} else {
echo "File1 does not exist | ";
}

// Check file2
if (!empty($file2['name'])) {
//do your code to move and rename file1
echo "File2 Exists | ";
} else {
echo "File2 does not exist | ";
}

// Check file3
if (!empty($file3['name'])) {
//do your code to move and rename file1
echo "File3 Exists | ";
} else {
echo "File3 does not exist | ";
}

// Check file4
if (!empty($file4['name'])) {
//do your code to move and rename file1
echo "File4 Exists | ";
} else {
echo "File4 does not exist | ";
}

?>

<form enctype="multipart/form-data" method="post" name="upload_form">

<label for="file1">File 1: </label><input type="file" name="file1"></input><br /><br />
<label for="file1">File 2: </label><input type="file" name="file2"></input><br /><br />
<label for="file1">File 3: </label><input type="file" name="file3"></input><br /><br />
<label for="file1">File 4: </label><input type="file" name="file4"></input><br /><br />
<input type="submit" value="upload">

</form>
[/code]

[Ninjakreborn]

100% perfect.  Exactly what I needed.  I owe this one thank's to you, I was having a hard time explaining it.  Thanks, if you hadn't of then I would have been fighting with this awhile.
Thanks again this is exactly what I needed.

[Ninjakreborn]

so me doing
$file1 = $_FILES['file1'];
the I can access all the variables using like
$file['file1']['name']
and
$file1['file1']['tmp_name']
like that
is that why you grabbed them all.

[gmwebs]

Well instead of using the long [code=php:0]$_FILES['file1']['name'][/code] by assigning a variable to the respective [code=php:0]$_FILES['input_name'][/code] you are able to access each attribute of the respective variable directly [code=php:0]$file1['tmp_name'][/code]. I hope that explains it? You certainly don't [i]have[/i] to use my method, I just find it easier to work with.

[Ninjakreborn]

Of course I will, it make's less typing, I was just making sure I understood it right.

[roopurt18]

I find it ironic you'd want to assign $_FILES['form_param'] to another variable to save typing yet you didn't want to use a single loop and would rather type the same code thirty times over.

World works in mysterious ways I guess!

;)

[gmwebs]

lol... In all fairness it was my code that suggested he assign a variable to [code=php:0]$_FILES['input_name'][/code] but yeah, fair point ;)

[Ninjakreborn]

The reason I am not, is because I don't know how. I have "always" had trouble's with file uploads.  Every single time I try I run into problems' I think doing array uploads will make it even harder for me specifically until I master how they work.

For instance, right now I ran into a problem

[code]<?php
$target = "/oakley/propimages/"; // prepare target url this is the same for all images,(since it
// is the same location on all images)
$file1 = $_FILES['file1'];
if (!empty($file1['name'])) {
$tmp_name1 = $file1['tmp_name'];
$name1 = $id . "_" . $file1['name'];
$target1 = $target . $name1;
if (file_exists($target1)) {
echo "File 1 already exists.<br />";
}else {
if (move_uploaded_file($tmp_name1, $target1)) {
echo "File was uploaded successfully.<br />";
}else {
echo "There was a problem uploading this specific file.<br />";
echo $tmp_name1;
echo $name1;
echo $target1;
}
}
} else {
echo "File1 does not exist | ";
}
?>[/code]
Once I get this working I am going to replicate it for the rest.
I tried this one code, the reason I am doing it this way, I have to rename the code for each image to the propertynumber_imagename
I am having to do that on all of htem, I used that code up there, and tested it out on the first upload, and got this error.
[quote]Status on File 1

Warning: move_uploaded_file(/oakley/propimages/1_cup.jpg) [function.move-uploaded-file]: failed to open stream: No such file or directory in /homepages/30/d162063315/htdocs/oakley/admin/addimages2.php on line 77

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/php3H9i9j' to '/oakley/propimages/1_cup.jpg' in /homepages/30/d162063315/htdocs/oakley/admin/addimages2.php on line 77
There was a problem uploading this specific file.
/tmp/php3H9i9j1_cup.jpg/oakley/propimages/1_cup.jpg[/quote]

the variable echo's that was only for debugging purposes by the way

[kenrbnsn]

The first warning message is telling you that the destination directory (or file) is not writable. Does the directory "[b]/oakley/propimages/[/b]" exist? Is it writable by everyone?

I believe you really want the directory "[b][color=blue]oakley/propimages/[/color][/b]". Notice the first slash is missing, which makes the directories subdirectories of the current working directory.

Ken