perplexia Posted July 18, 2012 Share Posted July 18, 2012 I'm trying to insert new data into a MS Access database using php. I get the following error" Fatal error: Uncaught exception 'com_exception' with message '<b>Source:</b> ADODB.Connection<br/><b>Description:</b> Operation is not allowed when the object is closed.' in C:\wamp\www\Jim_Langeveld\insert.php on line 37 Here's my code for the form: <?php require_once("connect.php"); include('menu.html'); ?> <form action="insert.php" name="add_header" method="post"> <fieldset> <p><label for="vendor">Vendor </label><input name="vendor" id="vendor" type="text" size="30" /></p> <p><label for="date">Date </label><input name="date" id="date" type="text" size="12" /></p> <p><label for="invoice">Invoice </label><input name="invoice" id="invoice" type="text" size="20" /></p> <p><label for="total">Total Amount </label><input name="total" id="total" type="text" size="8" /></p> <p><label for="tax">Tax Amount </label><input name="tax" id="tax" type="text" size="8" /></p> </fieldset> <input type="submit" name="submit" value="submit"> </form> </body> </html> and here is the code for insert.php <?php require_once("connect.php"); include('menu.html'); $vendor = mysql_real_escape_string($_POST['vendor']); $date = mysql_real_escape_string($_POST['date']); $invoice = mysql_real_escape_string($_POST['invoice']); $total = mysql_real_escape_string($_POST['total']); $tax = mysql_real_escape_string($_POST['tax']); $insert = "INSERT INTO tblPurchasesHeader (Vendor, InvoiceDate,Invoice,TotalAmount,TaxAmount) VALUES (".$vendor."','".$date."','".$invoice."','".$total."','".$tax."')"; $conn->Execute($insert); echo "The information has been submitted."; ?> Thank you for your help! Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/ Share on other sites More sharing options...
Donald. Posted July 18, 2012 Share Posted July 18, 2012 I might be wrong as I'm not a pro, but try the following. Replace: $conn->Execute($insert); echo "The information has been submitted."; With: if(mysql_query($insert)){ echo "The information has been submitted."; } Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362334 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 Thanks Donald! That's a great suggestion. I tried it and now I don't get any error message, but it still does not insert the new data into the database. Basically nothing happens. I thought I needed the "execute" command because it was MS Access... but I'm not sure. Any idea why it's not inserting the data? Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362645 Share on other sites More sharing options...
andrew_biggart Posted July 19, 2012 Share Posted July 19, 2012 With most insert issues it's normally a spelling error with one or the variables, table names within the actual sql query. Double check everything is exactly how it should be. I don't think you need the following either. Your variables are currently like this ".$vendor."' but all you really need is this '$vendor' . Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362655 Share on other sites More sharing options...
Donald. Posted July 19, 2012 Share Posted July 19, 2012 With most insert issues it's normally a spelling error with one or the variables, table names within the actual sql query. Double check everything is exactly how it should be. I don't think you need the following either. Your variables are currently like this ".$vendor."' but all you really need is this '$vendor' . You're totally right, he missed the first ' in the insert statement. This should do the trick. $insert = "INSERT INTO tblPurchasesHeader (Vendor, InvoiceDate,Invoice,TotalAmount,TaxAmount) VALUES ('".$vendor."','".$date."','".$invoice."','".$total."','".$tax."')"; Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362662 Share on other sites More sharing options...
andrew_biggart Posted July 19, 2012 Share Posted July 19, 2012 I still don't think you need the ". before and ." after each variable either. But I maybe wrong. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362668 Share on other sites More sharing options...
boompa Posted July 19, 2012 Share Posted July 19, 2012 Sort of an aside, having not using MS Access for the last 15+ years and never from PHP. I'm a bit perplexed as to why you'd use mysql_real_escape_string on values being passed to an Access database? Does that work? Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362682 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 Sort of an aside, having not using MS Access for the last 15+ years and never from PHP. I'm a bit perplexed as to why you'd use mysql_real_escape_string on values being passed to an Access database? Does that work? I guess it was just a habit. I don't know if it works - haven't tested it. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362696 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 I still don't think you need the ". before and ." after each variable either. But I maybe wrong. Thanks for you help! it's always something simple! Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362697 Share on other sites More sharing options...
cyberRobot Posted July 19, 2012 Share Posted July 19, 2012 I still don't think you need the ". before and ." after each variable either. But I maybe wrong. That is correct. Since the overall string is within double quotes, the following should work: <?php $insert = "INSERT INTO tblPurchasesHeader (Vendor, InvoiceDate,Invoice,TotalAmount,TaxAmount) VALUES ('$vendor','$date','$invoice','$total','$tax')"; ?> Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362699 Share on other sites More sharing options...
Barand Posted July 19, 2012 Share Posted July 19, 2012 Sort of an aside, having not using MS Access for the last 15+ years and never from PHP. I'm a bit perplexed as to why you'd use mysql_real_escape_string on values being passed to an Access database? Does that work? mysql_real_escape_string() requires a mysql connection therefore it won't work. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362704 Share on other sites More sharing options...
andrew_biggart Posted July 19, 2012 Share Posted July 19, 2012 Please mark this topic as solved. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362708 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 Please mark this topic as solved. I will - as soon as I can test it to see if it works. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362738 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 hmmm... all your replies make perfect sense to me, but it's still doesn't work for some reason. I don't get any error messages, but it doesn't insert the data into the DB. Maybe there's a problem with the database itself? could it have something to do with the format of the columns ie: number, text, date, currency? Here's my updated code: //declare variables $vendor = ($_POST['vendor']); $date = ($_POST['date']); $invoice = ($_POST['invoice']); $total = ($_POST['total']); $tax = ($_POST['tax']); //insert the data $insert = "INSERT INTO tblPurchasesHeader (Vendor,InvoiceDate,Invoice,TotalAmount,TaxAmount) VALUES ('$vendor','$date','$invoice','$total','$tax')"; if(mysql_query($insert)) { echo "your information was submitted"; } else { echo "your information was not submitted"; } Thanks again for all your help! Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362791 Share on other sites More sharing options...
cyberRobot Posted July 19, 2012 Share Posted July 19, 2012 Have you tried going back to your original code for executing the query? <?php $conn->Execute($insert); ?> I would imagine that the Execute() method handles the mysql_query() part. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362795 Share on other sites More sharing options...
Jessica Posted July 19, 2012 Share Posted July 19, 2012 Are you doing Access or MySQL? If you're using Access, none of your variables will be correct, and should cause errors. The original code is using the ADODB library. At the top of the code add error_reporting(E_ALL); ini_set('error_reporting', 1); Then change $conn->Execute($insert); to: if ($conn->Execute($insert) === false) { print "<p>SQL: $insert <br>Error: {$conn->ErrorMsg()}</p>"; } Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362797 Share on other sites More sharing options...
perplexia Posted July 19, 2012 Author Share Posted July 19, 2012 Have you tried going back to your original code for executing the query? <?php $conn->Execute($insert); ?> I would imagine that the Execute() method handles the mysql_query() part. yes, when I do that I get this error: Fatal error: Uncaught exception 'com_exception' with message '<b>Source:</b> ADODB.Connection<br/><b>Description:</b> Operation is not allowed when the object is closed Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362805 Share on other sites More sharing options...
andrew_biggart Posted July 20, 2012 Share Posted July 20, 2012 Not sure if this is making a difference but I think there may be a problem with how you are declaring your variables. Try changing this: $vendor = ($_POST['vendor']); $date = ($_POST['date']); $invoice = ($_POST['invoice']); $total = ($_POST['total']); $tax = ($_POST['tax']); to this: $vendor = $_POST['vendor']; $date = $_POST['date']; $invoice = $_POST['invoice']; $total = $_POST['total']; $tax = $_POST['tax']; Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1362977 Share on other sites More sharing options...
jcbones Posted July 20, 2012 Share Posted July 20, 2012 You are not connected to the database, the error tells you the source of the problem is the connection, and the reason is that the object is closed. You need to go back and check your connections to see why it isn't open. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1363040 Share on other sites More sharing options...
xyph Posted July 20, 2012 Share Posted July 20, 2012 You still haven't cleared up the most important part. Are you using MS Access or MySQL? Where is $conn defined? What kind of object does it hold? Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1363063 Share on other sites More sharing options...
perplexia Posted July 31, 2012 Author Share Posted July 31, 2012 ...Are you using MS Access or MySQL?... I am using MS Access. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1365583 Share on other sites More sharing options...
perplexia Posted July 31, 2012 Author Share Posted July 31, 2012 Where is $conn defined? What kind of object does it hold? $insert = "INSERT INTO tblPurchasesHeader (Vendor, InvoiceDate,Invoice,TotalAmount,TaxAmount) VALUES (".$vendor."','".$date."','".$invoice."','".$total."','".$tax."')"; $conn->Execute($insert); Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1365585 Share on other sites More sharing options...
perplexia Posted July 31, 2012 Author Share Posted July 31, 2012 Have you tried going back to your original code for executing the query? <?php $conn->Execute($insert); ?> yes, I am using this code presently, but I still get a "object closed" error. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1365586 Share on other sites More sharing options...
perplexia Posted July 31, 2012 Author Share Posted July 31, 2012 You are not connected to the database, the error tells you the source of the problem is the connection, and the reason is that the object is closed. You need to go back and check your connections to see why it isn't open. makes sense to me. how do I check the connection? Thanks. Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1365589 Share on other sites More sharing options...
perplexia Posted July 31, 2012 Author Share Posted July 31, 2012 Where is $conn defined? What kind of object does it hold? ...sorry, I think this is what you were looking for: $conn is defined in connect.php as $conn = new COM ("ADODB.Connection") or die("Cannot start ADO"); Quote Link to comment https://forums.phpfreaks.com/topic/265871-insert-doesnt-work-help-please-and-thank-you/#findComment-1365594 Share on other sites More sharing options...
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