Running An Insert Query Grabbing The Id And Updating Another Table With Id

[garrickplaisted]

I need to insert a new row in to a table, then grab the ID of taht row and update another table.

What I have is something like this:

$sql="INSERT INTO leads (field1, field2) VALUES('$value1','$value2')";
$query = mysql_query($sql);
$lastID = mysql_insert_id();
$update = "UPDATE contacts SET leadID = $lastID WHERE contactID = $contactID";
$updateQuery = mysql_query($update);

 

Everything works fine.. except that it inserts duplicate rows into the leads table. I have tried putting the update query into an if statement and it did the samething(this was just to try "something"). If I remove $lastID = mysql_insert_id(); it inserts just one row but obviously does not update the contacts table. So I am pretty sure it has to to with mysql_insert_id(). I need it to update the contacts table with the new id of the row inserted into the leads table. Any ideas would be greatly appreciated.

[requinix]

mysql_insert_id() by itself will not cause this problem. How about posting the rest of your code, and the real stuff this time?

Edited December 19, 2012 by requinix

[garrickplaisted]

Here it is, thanks!

$leadSQL="INSERT INTO $leadsTable (leadName, leadStatus, leadDescription, leadOpportunity, leadSource, leadSourceDescription, id, leadSince, contactID)
		 VALUES ('$_POST[leadName]', '$_POST[leadStatus]', '$_POST[leadDescription]', '$_POST[leadOpportunity]', '$_POST[leadSource]', '$_POST[leadSourceDescription]','$_POST[id]','$leadSince','$_POST[contactID]')";
$leadQuery = mysql_query($leadSQL);

$lastLeadID = mysql_insert_id();
$updateContactSQL = "UPDATE $contactsTable SET leadID = $lastLeadID WHERE contactID = $_POST[contactID]";
$updateContactQuery = mysql_query($updateContactSQL);

Edited December 19, 2012 by garrickplaisted