mysql_fetch_array() expects parameter 1 to be resource

[hazm]

I face same problem but different program...

 

 <?php

$c=$_REQUEST['course'];

$link = mysql_connect('localhost', 'root', ''); //change the configuration in required

if (!$link) {

    die('Could not connect: ' . mysql_error());

}

mysql_select_db('subject');

print $c;

?>

<select name="subject">

<option>Select Subject</option>

<?php 

$kus= mysql_query("SELECT * FROM subject");

while($row9 = mysql_fetch_array($kus)) 

{ 

echo "<option value='$row9[subid]'>$row9[subname]</option>";

}

?> 

</select>

 

[Jessica]

See the link in my signature, you need to check for MySQL errors.

 

Do you really have the database named subject AND your table named subject?

[lilmer]

Try to include this on your query or in every php sql command

 

 

or die(mysql_error());

[Sanjib Sinha]

Please do the error checking. http://php.net/manual/en/function.mysql-query.php

[Christian F.]

Echo much..?

 

Jessica already posted the answer, no need to repeat what she said. Especially with even less information. Better to spend your time, and energy, on someone who actually needs (more) help.