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Warning: mysql_num_rows() expects parameter 1 to be resource

grifb

By grifb
in PHP Coding Help

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grifb Newbie

grifb

Posted
Posted

help!!! i have been trying things all day with this and it wont work!

 

<html>
<div align="center">

<?php

$key = $_POST['key'];
$answer = $_POST['answer'];
$username = $_POST['username2'];

$item = explode(" ", $key);
$final = $item[0];
$removals = array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");
$lower = str_replace($removals, "", $final);
$newkey = strtolower($lower);

$areplace = str_replace("," , "', '", $answer);
$buff = "['$areplace']";
$finalanswer = strtolower($buff);

if ($key&&$username&&$answer) 
{

$connect = mysql_connect("fakedatabase","fakeuser", "fakepassword") or die("Couldn't Connect");
mysql_select_db("wordlist") or die("No Table");

$query = mysql_query("SELECT * FROM keylist WHERE keys='$newkey'");

$numrows = mysql_num_rows($query);

echo $numrows;
if ($numrows!=0)
{
$queryadduser1 = mysql_query("INSERT INTO userkeys Values('$username', 'Tried : $newkey')") or die("Unable to connect");
die("The key '$newkey' has already been added!");

} 
else 

$queryadd = mysql_query("INSERT INTO keylist Values('$newkey')") or die("Unable to connect");
$queryadd2 = mysql_query("INSERT INTO KeysAndAnswers Values('$newkey', '$finalanswer')") or die("Unable to connect");
$queryadduser1 = mysql_query("INSERT INTO userkeys Values('$username', 'Added : $newkey ')") or die("Unable to connect");
echo("The key '$newkey' and the answer '$finalanswer' Has just been submitted! Thank you!");
}
else
  die("Key or answer or username  was blank");

?>

</div>
</html>

 

 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'keys='123-123'' at line 1

 

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