Cron Job Problem

[mostafatalebi]

Hello everybody

 

I have set up a cronJob but it keeps sending error report to my mail.

 

These are the errors:

(I have removed the full server path before the cron.php which is home/..../)

cron.php: line 1: ?php: No such file or directory

cron.php: line 2: /backup: is a directory
cron.php: line 3: access-logs: command not found
cron.php: line 4: access-logs: command not found
cron.php: line 5: access-logs: command not found
cron.php: line 6: access-logs: command not found
cron.php: line 7: access-logs: command not found
cron.php: line 8: access-logs: command not found
cron.php: line 9: access-logs: command not found
cron.php: line 10: access-logs: command not found
cron.php: line 11: access-logs: command not found
cron.php: line 12: access-logs: command not found
cron.php: line 13: access-logs/: is a directory
cron.php: line 16: //: is a directory
cron.php: line 17: syntax error near unexpected token `('
cron.php: line 17: `$mydir = dirname(__FILE__);'

 

 

 

 

What shall I do?

 

[trq]

Looks like cron is trying to execute a php file using bash.

 

You need to tell cron you are executing a php file.

[requinix]

Either that or use a shebang at the very beginning:

#!/usr/bin/php
<?php

// ...

(Your path to the php binary may vary.)

[mostafatalebi]

so how I should tell it that i am executing a php file?

[trq]

As requinix just said, use a shebang.

[PaperTiger]

If you want to execute a PHP file in the cron, you need to specify the path to the PHP command line interpreter. If you're using linux, this is generally "/usr/bin/php"

 

So the cron would look like:

 

* * * * * /usr/bin/php /path/to/file.php

 

Replacing * for whatever time values you actually want

[trq]

If you want to execute a PHP file in the cron, you need to specify the path to the PHP command line interpreter.

Or, do as has already been suggested and use a shebang as other scripts on Unix do.