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Hi Everyone

 

This stuff is well beyond my understanding.

 

I have been using the code below written by JKG http://forums.phpfreaks.com/topic/234954-how-to-get-the-value-of-subdomain/?hl=%2Bfind+%2Bsubdomain&do=findComment&comment=1208823  And it has been working flawlessly, until I ran into something unexpected. 

 

It doesn't work with usernames (subdomains) that contain a dot "." For instance john.doe http://www.john.doe.mysite.com

<?php
$url = "http://" . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'] . $_SERVER['QUERYSTRING'];
$urlParts = explode('.', $_SERVER['HTTP_HOST']);
if(strpos($url, 'www')){
$subdomain_value = $urlParts[1];
} else { 
$subdomain_value = $urlParts[0]; 
};
echo $subdomain_value;
?>

For my application, anything between the www. and .mysite.com is the subdomain ie username. So with http://www.this.is.the.username.mysite.com username =  this.is.the.username  Although I have not run across anyone with more then one dot in their username, the possibility exists. Doubtful if any username would have more than 2 dots.

 

Background info: I have wildcard subdomain redirected to root. Works without needing any htaccess. The subdomain is just a placeholder for username. Then I use php to pull out the username (subdomain) and retrieve their saved info from mysql.

 

As I said, I am way over my head. Anyone know of a solution? 

 

Thanks Tom

 

 

 

 

 

 

 

 

 

 

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Thankyou for the reply trq and requinix

 

I have not been using the PHP_SELF or QUERY_STRING parts so the error hasn't shown up.

 

I am googling for preg_match() and subdomain, so far every example I have seen is trying to either replace the subdomain or alter css for a particular subdomain, anything but retreive the subdomain.

 

Found this in http://ca2.php.net/preg_match  which returns php.net (domain and TLD)

<?php
// get host name from URL
preg_match('@^(?:http://)?([^/]+)@i',
    "http://www.php.net/index.html", $matches);
$host = $matches[1];

// get last two segments of host name
preg_match('/[^.]+\.[^.]+$/', $host, $matches);
echo "domain name is: {$matches[0]}\n";
?>

So would the code start out something like this? 

<?php
$url = "http://" . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'] ? $_SERVER['QUERY_STRING'];
$urlParts = preg_match(????, $_SERVER['HTTP_HOST'], $matches);

I assume the idea is to match out the http://www. and the .mydomain.com and anything left between is the subdomain.

 

This is really outside of my meager knowledge of php.

 

Any help would be appreachiated.

 

Thnaks Tom

 

 

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Take a look at this regular expression which I've builded for you.

 

Next URL's will be matched:

<?php 

// https://www.john.doe.mysite.com
// https://www.john.doe.mysite.com/
// http://www.john.doe.mysite.com
// http://www.john.doe.mysite.com/
// https://john.doe.mysite.com
// https://john.doe.mysite.com/
// http://john.doe.mysite.com
// http://john.doe.mysite.com/
// www.john.doe.mysite.com
// www.john.doe.mysite.com/

// OR their variants
// http://www.test.doe.my.siteName.mysite.com/


// get host name from URL
$host = "http://test.doe.mysite.com/";

preg_match('/((\bhttps?:\/\/(www.)?|\bwww\.)([a-z.]+)?\.([a-z]+\.[a-z]{2,4}(\/)?)$)/i', $host, $matches);

echo '<pre>'.print_r($matches, true).'</pre>';

If you want to get only the prefix, domain, sub-domain, etc....just call the array, something like:

echo "My domain name is: ".$matches[5];

echo "My sub-domain name is: ".$matches[6];

Hope, this will help you.
        
jazz..

Edited by jazzman1
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So, few things:

 

If you want to match the URL only as domain name for example -  $host = "http://mysite.com/", this regEx won't work b/s we need to make a period optional before the domain name.

 

Take that:

preg_match('/((\bhttps?:\/\/(www.)?|\bwww\.)([a-z.]+)?\.?([a-z]+\.[a-z]{2,4}(\/)?)$)/i', $host, $matches);
Edited by jazzman1
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I'm pretty sure this thread is spiraling away from the really simple problem of removing "www" and "mysite.com" from the HTTP_HOST.

$host = "www.john.smith.mysite.com"; // $_SERVER["HTTP_HOST"]
if (strncmp($host, "www.", 4) == 0) {
    $host = substr($host, 4);
}
if (substr_compare($host, ".mysite.com", -11 /* -strlen(".mysite.com") */) == 0) {
    $host = substr($host, -11);
}
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Thank you requinix  and  jazzman1

 

As long as requinix solution works with usernames that contain dots or dashes, simple is always better to me.

 

http://www.any.user-name.mysite.com username = any.user-name

 

http://any.user-name.mysite.com username = any.user-name  (with or without www)

 

I have been reading for hours goggle searches on ``preg_match() subdomain url`` and not geting anywhere, except very confused.

 

requinix so at the end of your script does $host = username

 

 

Since I am not scanning random urls, RegEX did seem like overkill. In the past few hours I have read more RegEX expressions then I care to count, not that I understood any of them.

 

Thanks again

Edited by liberate
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@libarate, don't underestimate the power of RegEx....

 

If you want to match links that contains a "-" symbol just add it between the square brackets, containing sub-domain expression.

 

Example:

// get host name from URL
$host = "http://www.any.user-name.mysite.com";

preg_match('/((\bhttps?:\/\/(www.)?|\bwww\.)([a-z.-]+)?\.?([a-z]+\.[a-z]{2,4}(\/)?)$)/i', $host, $matches);

echo '<pre>'.print_r($matches, true).'</pre>';

Results:

Array
(
    [0] => http://www.any.user-name.mysite.com
    [1] => http://www.any.user-name.mysite.com
    [2] => http://www.
    [3] => www.
    [4] => any.user-name.mysit
    [5] => e.com
)
Edited by jazzman1
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Ops.....my typo sorry for that:

<?php 

// get host name from URL
$host = "http://www.any-user.name.mysite.com";

preg_match('/((\bhttps?:\/\/(www.)?|\bwww\.)([a-z.-]+)?\.([a-z]+\.[a-z]{2,4}(\/)?)$)/i', $host, $matches);

echo '<pre>'.print_r($matches, true).'</pre>';

Results:

Array
(
    [0] => http://www.any-user.name.mysite.com
    [1] => http://www.any-user.name.mysite.com
    [2] => http://www.
    [3] => www.
    [4] => any-user.name
    [5] => mysite.com
)
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Hi jazzman1

 

I don't underestimate the power of RegEx just don't understand it.

 

 

So array [4] is always the username?

 

 

Does this work?

<?php 

$host = "$_SERVER["HTTP_HOST"]";
preg_match('/((\bhttps?:\/\/(www.)?|\bwww\.)([a-z.-]+)?\.([a-z]+\.[a-z]{2,4}(\/)?)$)/i', $host, $matches);

$user = $matches[4];

Thanks Tom

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How would you use $host = http://www.any-user.name.mysite.com; ?

 

 

For lack of the technical way of saying it.....The script needs to retrieve the url from the address bar.

 

When a registered member comes to mysite.com they use their personal url http://www.their-username.mysite.com or http://their-username.mysite.com or http://theirusername.mysite.com

 

It is a multi-user self-replicating site. The admin.php file then retrieves the username from the "address bar"  and looks up the rest of their info from mysql.

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Ok, I've created a new one that will get all posible variants to this moment.

 

The sub-domain always will be -  $user = $matches[4];

 

The domain - $user = $matches[5];

 

You can use $host = $_SERVER["HTTP_HOST"] to get the domain (sub-domain) name for every user.

 

Next URL's will be matched:

<?php

// http://www.test-net.mysite.com
// https://www.test-net.mysite.com/
// www.test-net.mysite.com
// test-net.mysite.com
// http://mysite.com (only with domain name)
// etc......

    // get host name from URL
    $host = "canada.host-name.mysite.com";
     
    preg_match('/^((\bhttps?:\/\/(www.)?|\bwww\.)?([a-z.-]+)?\.)?([a-z]+\.[a-z]{2,4}\/?)$/i', $host, $matches);
     
    echo '<pre>'.print_r($matches, true).'</pre>';
Edited by jazzman1
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Hi jazzman1

 

You're up late. I live about 1 1/2 hours from you.

 

So in my admin.php I would do.

<?php 

$host = $_SERVER["HTTP_HOST"];

preg_match('/^((\bhttps?:\/\/(www.)?|\bwww\.)?([a-z.-]+)?\.)?([a-z]+\.[a-z]{2,4}\/?)$/i', $host, $matches);

$user = $matches[4];

And then look up $user in mysql.

 

I will give it a try.

 

Thanks

Tom

my email liberate at uc2 dot biz (old address that gets lots of spam) email me. 

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I put this into the top of my_admin.php

<?php 

$host = $_SERVER["HTTP_HOST"];

preg_match('/^((\bhttps?:\/\/(www.)?|\bwww\.)?([a-z.-]+)?\.)?([a-z]+\.[a-z]{2,4}\/?)$/i', $host, $matches);

// $user = $matches[4];

echo '<pre>'.print_r($matches, true).'</pre>';

echo returned empty

Array()

I assume I am doing something wrong.

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You are doing something wrong:

  // get host name from URL
    $host = "http://www.liberate.mysite.com/";
     
    preg_match('/^((\bhttps?:\/\/(www.)?|\bwww\.)?([a-z.-]+)?\.)?([a-z]+\.[a-z]{2,4}\/?)$/i', $host, $matches);
     
    echo '<pre>'.print_r($matches, true).'</pre>';

Results:

Array
(
    [0] => http://www.liberate.mysite.com/
    [1] => http://www.liberate.
    [2] => http://www.
    [3] => www.
    [4] => liberate
    [5] => mysite.com/
)

But.... it's too late for me :)

 

I'm going bed.

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Good night jazzman1 :sleeping:

 

So $host has to be a known variable? Then I don't see how this can work. Username changes each time a different member comes to the site.

 

My username might be liberate, but what about the other users? $host = "http://www.liberate.mysite.com/";  would program the site only to work for me.

 

Am I missing something here?

 

Tom

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Going back to @requinix script

 

 

I put this into the top of my_admin.php

<?php 

$host = $_SERVER["HTTP_HOST"]; i
if (strncmp($host, "www.", 4) == 0) {
    $host = substr($host, 4);
}
if (substr_compare($host, ".mysite.com", -11 /* -strlen(".mysite.com") */) == 0) {
    $host = substr($host, -11);
}

echo $host;

Echo returned:

liberate.mysite.com

 

So $host is not subdomain but contains both sub and domain, and yes I did alter the "mysite.com" in the code to the real domain.com.

 

Something not quite right.

Edited by liberate
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