If URL then script

[Mucker]

The first block of code is what i want to use since i know it works, but i dont know how to use it with the code already there.

<?php

 if
 (strpos($_SERVER['REQUEST_URI'], 'upload.php') == false) {
echo 'the stuff below is removed, or if the URL is something else, its not removed'
?>

This code is already in my form and can not be changed!!! This is what I want to remove totally if the URL is upload.php

<div class="navbar" name"navbar" Id="navbar">
    <div class="navbar-inner" name="navbar-inner" Id="navbar-inner">'     
      <?php  echo  a_view('core/account/login_dropdown'); ?>
      <?php  echo  a_view_menu('topbar', array('sort_by' => 'priority', array('menu-hz'))); ?>
       <?php echo  a_view('search/search_box', array('class' => 'search-header')); ?>
    </div>
</div>

Can anyone help?

[requinix]

if (you do want to show that stuff) {


?>

the stuff


}


?>

[ginerjm]

Have no idea what you are trying to do, but try this.

 

 

<?php  

if  (strpos($_SERVER['REQUEST_URI'], 'upload.php') == false)

{

   echo 'the stuff below is removed, or if the URL is something else, its not removed'

}

else

{

   echo '<div class="navbar" name"navbar" Id="navbar">';    

   echo '<div class="navbar-inner" name="navbar-inner" Id="navbar-inner">';          

   echo  a_view('core/account/login_dropdown');

   echo  a_view_menu('topbar', array('sort_by' => 'priority', array('menu-hz') ) );

   echo  a_view('search/search_box', array('class' => 'search-header'));

   echo '</div> </div>';

}

 

This would prevent the second part from being output.

 

Note - there is at least one error in that code, so I don't think it's working as shown.  Also your first if statement is backwards if you want the "else" stuff dropped if the uri is upload.php

[Mucker]

Have no idea what you are trying to do, but try this.

 

 

<?php  

if  (strpos($_SERVER['REQUEST_URI'], 'upload.php') == false)

{

   echo 'the stuff below is removed, or if the URL is something else, its not removed'

}

else

{

   echo '<div class="navbar" name"navbar" Id="navbar">';    

   echo '<div class="navbar-inner" name="navbar-inner" Id="navbar-inner">';          

   echo  a_view('core/account/login_dropdown');

   echo  a_view_menu('topbar', array('sort_by' => 'priority', array('menu-hz') ) );

   echo  a_view('search/search_box', array('class' => 'search-header'));

   echo '</div> </div>';

}

 

This would prevent the second part from being output.

 

Note - there is at least one error in that code, so I don't think it's working as shown.  Also your first if statement is backwards if you want the "else" stuff dropped if the uri is upload.php

Can you define how it's backwards? I am working on a website with a friend, and we are just stuck on this bit. If you could fix the code, I would be most greatful

[Mucker]

I can't edit my post so i am bumping it to explain what i need. Basically ginerjm from the second block of code. Thats from another php script, but i need to exclude that php script becuase I don't want it visible on the page i am working on, but I need it visible on other pages.

[ginerjm]

And that's what I deduced.

 

As for your error.

 

Your original post:

<?php  

if  (strpos($_SERVER['REQUEST_URI'], 'upload.php') == false)

{

   echo 'the stuff below is removed, or if the URL is something else, its not removed'

?>

 

is flawed.  You are missing the closing curly bracket as well as a semi at the end of the echo.  So obviously you've never run this code.

 

Anyway this statement says "if the uri does NOT contain 'upload.php' show the message 'stuff is removed'.   You were close - you just have to include the code that you wanted to remove.  So - taking my post and correcting it you would have:

 

<?php  

if  (strpos($_SERVER['REQUEST_URI'], 'upload.php') == false)

{

   echo '<div class="navbar" name"navbar" Id="navbar">';     // this line has an error

   echo '<div class="navbar-inner" name="navbar-inner" Id="navbar-inner">';          

   echo  a_view('core/account/login_dropdown');   // I'm assuming that "a_view" is some function defined somewhere

   echo  a_view_menu('topbar', array('sort_by' => 'priority', array('menu-hz') ) );   // again - a function call?

   echo  a_view('search/search_box', array('class' => 'search-header'));

   echo '</div> </div>';

}

 

Now the code will NOT be displayed if the uri contains your script name.

Edited June 18, 2013 by ginerjm

[Mucker]

thank you very much friend