unserialize within a foreach within a while loop

[showme48]

Hello,

I'm trying to unserialize a string and then
compare it and if listed mark the checkbox
as CHECKED.

It works fine as long as I have 1,2,3,4 checked
but if I do something like 1,4 then it only shows
1 as being CHECKED

 

Any help would be appreciated.

 

Thanks in advance.

function getm($id) {

$query3 = "select memtype from offer WHERE id = '".$id."'";
		$result3 = mysql_query ($query3)
            		or die ("Query failed");
                $line3 = mysql_fetch_array($result3);
		$memtype = $line3["memtype"];

$mydata = unserialize($memtype);

echo '<tr bgcolor=#CCCCCC><td>';
echo 'Show to:</td><td>';

if(!empty($mydata)) {

foreach( $mydata as $key => $value) {
 $gamenames[] = $key;
     }

}


$getaccountinfo = mysql_query("Select id, mem_name, mem_rank from `memtype` WHERE mem_enabled=1 ORDER BY id ASC");

for ($j = 0; $j < mysql_num_rows($getaccountinfo); $j++) {
$offerid = mysql_result($getaccountinfo, $j, "id");
$memname = mysql_result($getaccountinfo, $j, "mem_name");
echo(" $gamenames[$j] <input type=checkbox name=memtype[$offerid] value=$offerid"); if($gamenames[$j]==$offerid){echo(" CHECKED");} echo(">$memname <br>");
}

echo '</td></tr>';

}


$sql = mysql_query("SELECT * FROM offer");

echo '<table border=0><tr><td>';
                        while($oto = mysql_fetch_array($sql)) {
                        if($count==1)
			{
				echo "</td><td>";
				$count=0;
			}
			$count++;
        	  ?>

 <h3 align=center>OFFER <?php echo $oto['id']; ?></h3>
		  <form method="POST">
		  <input type="hidden" name="action" value="updateoffer">
                  <input type="hidden" name="id" value="<?php echo $oto['id']; ?>">
		  <table border=0 cellpadding=5 bgcolor=#000000>
		   <tr bgcolor=#CCCCCC><td>Price:</td><td>$<input type="text" name="price" value="<?php echo $oto['price']; ?>"></td></tr>
		   <tr bgcolor=#CCCCCC><td>Commission:</td><td>$<input type="text" name="pdcommission" value="<?php echo $oto['pdcommission']; ?>"></td></tr>
                   <tr bgcolor=#CCCCCC><td>Show after login:</td><td><input type="radio" name="enable" value="1"<?php if($oto['enable'] == 1) echo " CHECKED"; ?>> yes <input type="radio" name="enable" value="0"<?php if($oto['enable'] == 0) echo " CHECKED"; ?>> no</td></tr> 
                 

		  
<?php

$showm=getm($oto['id']); 

?>


               
		   
                   <tr><td colspan="2" align="center"><input type="submit" value="Update"></td></tr>
                 </table>
                 </form>

<?php
        }
echo '</td></tr></table>';
?>

[jazzman1]

Change:

if($gamenames[$j]==$offerid){echo(" CHECKED")

TO

($gamenames[$j]==$offerid) ? ' CHECKED' : NULL;

[kicken]

Your values in $gamenames do not line up with your row counter values. When you select 1,4, then $gamenames[0] and $gamenames[1] are set, not $gamenames[0] and $gamenames[3] which is what your code would require as it is right now.

 

What you want to do is check whether $offerid exists anywhere within the $gamenames array, not if it exists specifically at $gamenames[$j]. You can do this by using the in_array function.

[showme48]

 

Change:

if($gamenames[$j]==$offerid){echo(" CHECKED")

TO

($gamenames[$j]==$offerid) ? ' CHECKED' : NULL;

 

Thanks jazzman1,  I tried that and it did not work.

 

I appreciate the effort but it has been solved.

[showme48]

Your values in $gamenames do not line up with your row counter values. When you select 1,4, then $gamenames[0] and $gamenames[1] are set, not $gamenames[0] and $gamenames[3] which is what your code would require as it is right now.

 

What you want to do is check whether $offerid exists anywhere within the $gamenames array, not if it exists specifically at $gamenames[$j]. You can do this by using the in_array function.

 

 

Thanks kicken,

 

That worked perfectly.

 

Sent you a tip...  Donation Sent (Unique Transaction ID #5GY846557U109843P)

[jazzman1]

 

Thanks jazzman1,  I tried that and it did not work.

 

Yes, I know Misread it