heeha Posted August 11, 2015 Share Posted August 11, 2015 Hey, I am new to programming including html or any kind. I was trying to get dns info via php Lets say we have a website example.com, and we output the info for it as $site= (dns_get_record( "example.com", DNS_ALL); print_r( $site); which output as Array ( [0] => Array ( [host] => example.com [class] => IN [ttl] => 3500 [type] => A [ip] => xxx.xxx.xx.xxx ) [1] => Array ( [host] => example.com [class] => IN [ttl] => 172002 [type] => NS [target] => ns1.example.com ) [2] => Array ( [host] => example.com [class] => IN [ttl] => 17002 [type] => NS [target] => ns2.example.com ) and so on ) but I dont want this info to be output like this. I want it to appear as echo :The name of host is" . $anyvariable['host']. "."; and which output it as The name of host is example.com. and same for the others values. or appear something like this on webpage not in array forms. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/ Share on other sites More sharing options...
requinix Posted August 11, 2015 Share Posted August 11, 2015 Use a foreach loop on $site. Each value will be an array that looks like the $anyvariable you want. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518451 Share on other sites More sharing options...
heeha Posted August 11, 2015 Author Share Posted August 11, 2015 Thanks, I get it a little bit. But the problem now I face is that, there are 5 array, there it shows the same out as 5 fives instead of showing just once. foreach( $site as $anyvariable) { echo "the name of the host is" .$anyvariable['host']. "." ; echo "<br>"; } and the output comes out as the name of the host is example.com the name of the host is example.com upto 5 times. How do i restricted it the the limit to 1 or the output the "echo" only the number of times i want to output it. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518452 Share on other sites More sharing options...
Ch0cu3r Posted August 11, 2015 Share Posted August 11, 2015 It is showing that line 5 times because dns_get_record( "example.com", DNS_ALL); returns a multidimensional array of each type of dns record for that domain. In your case $site is a multidimensional array, which contains 5 sub-arrays. In each of these sub-arrays there is a "host" key. Your foreach loop is looping through each of these sub-arrays and outputting the "host" key. This is why line "the name of the host is example.com" is outputted five times. If you only want to host to be outputted once, you need add logic to your foreach loop example $putput_host = false; foreach( $site as $anyvariable) { // check if the host has been outputted if(!$output_host) { echo "the name of the host is" .$anyvariable['host']. "." ; echo "<br>"; // set $output_host to true, we have outputted the host $putput_host = true; } } If you are doing is outputting the host, then have dns_get_record return only one dns record, such as DNA_A $site = dns_get_record( "example.com", DNS_A); echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; 1 Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518456 Share on other sites More sharing options...
heeha Posted August 11, 2015 Author Share Posted August 11, 2015 It is showing that line 5 times because dns_get_record( "example.com", DNS_ALL); returns a multidimensional array of each type of dns record for that domain. In your case $site is a multidimensional array, which contains 5 sub-arrays. In each of these sub-arrays there is a "host" key. Your foreach loop is looping through each of these sub-arrays and outputting the "host" key. This is why line "the name of the host is example.com" is outputted five times. If you only want to host to be outputted once, you need add logic to your foreach loop example $putput_host = false; foreach( $site as $anyvariable) { // check if the host has been outputted if(!$output_host) { echo "the name of the host is" .$anyvariable['host']. "." ; echo "<br>"; // set $output_host to true, we have outputted the host $putput_host = true; } } If you are doing is outputting the host, then have dns_get_record return only one dns record, such as DNA_A $site = dns_get_record( "example.com", DNS_A); echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; Thanks, I get it completely but I guess foreach loop is still needed to output the variable. $site= dns_get_record( "example.com", DNS_A); echo $site['host'] . 'ip address is ' .$site['ip']. '<br />'; doesnt output any values but adding foreach loops does as it's still inside the array. $site= dns_get_record( "example.com", DNS_A); foreach( $site as $anyvariable) { echo $anyvariable['host'] . 'ip address is ' .$anyvariable['ip']. '<br />'; } Tried several times after trying foreach loop, helped me get the values. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518476 Share on other sites More sharing options...
ginerjm Posted August 11, 2015 Share Posted August 11, 2015 Untested but s/b pretty close. $site= (dns_get_record( "example.com", DNS_ALL); ShowArray($site); //*********************** function ShowArray($arg) { foreach ($arg as $idx=>$val) { if (is_array($var)) { echo "<br>Array is<br>"; ShowArray($var); } else echo "$idx is $val<br>"; } } Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518479 Share on other sites More sharing options...
heeha Posted August 12, 2015 Author Share Posted August 12, 2015 It is showing that line 5 times because dns_get_record( "example.com", DNS_ALL); returns a multidimensional array of each type of dns record for that domain. In your case $site is a multidimensional array, which contains 5 sub-arrays. In each of these sub-arrays there is a "host" key. Your foreach loop is looping through each of these sub-arrays and outputting the "host" key. This is why line "the name of the host is example.com" is outputted five times. If you only want to host to be outputted once, you need add logic to your foreach loop example $putput_host = false; foreach( $site as $anyvariable) { // check if the host has been outputted if(!$output_host) { echo "the name of the host is" .$anyvariable['host']. "." ; echo "<br>"; // set $output_host to true, we have outputted the host $putput_host = true; } } If you are doing is outputting the host, then have dns_get_record return only one dns record, such as DNA_A $site = dns_get_record( "example.com", DNS_A); echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; Code 1. Doesnt work. I have tried. regarding code 2. It does work but the problem i face now is that $site = dns_get_record( "example.com", DNS_NS); print_r($site); //outputs : Array ( [0] => Array ( [host] => example.com [class] => IN [ttl] => 5 [type] => NS [target] => my-servers.net ) [1] => Array ( [host] => example.com [class] => IN [ttl] => 5 [type] => NS [target] => your-servers.net ) [1] => Array ( [host] => example.com [class] => IN [ttl] => 5 [type] => NS [target] => this-servers.net ) ) foreach($site as $anyvariable) { echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; //outputs the first value "ok" but doesnt out the rest of the name servers different ans output the value same for both. How do i output in way that each gets displayed with all the values for ns1 and ns2 and so on? Each target value is different. @ginerjm : tried code as is, doesnt output anything. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518559 Share on other sites More sharing options...
heeha Posted August 12, 2015 Author Share Posted August 12, 2015 Update, finally solved. I guess i saw it somewhere something wrong. It works lets say there are 4 name server for a site and 2 for another. how do i display using if or elseif statement that if only website has two NS it will only display 2 and if a site has 4 server it display 4only. As i m using table to display the data, I place 4 table rows so when a website has for ns it works fine but when other website has 2 NS, the remaining two (table data) doesnt work properly. Thanks. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518560 Share on other sites More sharing options...
heeha Posted August 12, 2015 Author Share Posted August 12, 2015 Update : Solved. It automatically parses each information and shows all the dns correctly. Works only with the following code, and rest of the code told by many other didn't get any oputput at all. DNS_ALL does work but it has problem in output due as too much complication in handling multidimensional arrays. Foreach loop is also needed. $site = dns_get_record( "example.com", DNS_A); echo $site['host'] . ' ip address is ' . $site['ip'] . '<br />'; Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518563 Share on other sites More sharing options...
ginerjm Posted August 12, 2015 Share Posted August 12, 2015 There was an extra ( in my sample code. If you had turned on php error checking you probably would have been informed of it. Quote Link to comment https://forums.phpfreaks.com/topic/297723-adding-correct-coding-in-arrays/#findComment-1518590 Share on other sites More sharing options...
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