Draw on screen with an if statement

[Revolutsio]

How can i get this code to work?

 

What I want to do is if the field platform2 has text in it then it will put some divs on the screen

   <?php
    if($game['platform2'] ==" "){?>
    <div class="field-container">
    <?php }else {?>
        <div class="field-container">
        <div class="title">
            Platform
        </div>    
        <div class="information">
            <?php echo $game['platform2']; ?>
        </div>
        <div class="title">
            Launcher
        </div>    
        <div class="information">
            <?php echo $game['launcher2']; ?>
        </div>
    </div>
    <?php }?>

 

[ginerjm]

This is how the code could look:

if($game['platform2'] ==" ")
	echo "<div class='field-container'>";
else
	echo "<div class='field-container'>
		<div class='title'>Platform</div>    
		<div class='information'>{$game['platform2']}</div>
		<div class='title'>Launcher</div>    
		<div class='information'>{$game['launcher2']}</div>
		</div>
		";

Problem is - you say you want to check if 'platform2' has text in it but you are testing if it has a space in it.  Perhaps you want to check if it is not equal to '' ?

[Revolutsio]

8 minutes ago, ginerjm said:

This is how the code could look:

if($game['platform2'] ==" ")
	echo "<div class='field-container'>";
else
	echo "<div class='field-container'>
		<div class='title'>Platform</div>    
		<div class='information'>{$game['platform2']}</div>
		<div class='title'>Launcher</div>    
		<div class='information'>{$game['launcher2']}</div>
		</div>
		";

Problem is - you say you want to check if 'platform2' has text in it but you are testing if it has a space in it.  Perhaps you want to check if it is not equal to '' ?

Yes that is what i would like to do

 

 

[ginerjm]

So change the if to match what output you want.  If plafrorm2 is empty (ie, == '') and you want to only show the one div then make it so.  If it is the other way change the if to <> ''

More importantly note how I altered your output style.  Entering and leaving php mode to do output is such a tedious method of coding when you can avoid it by STAYING in php mode and using the echo.  Or by reading up on php's "heredocs" command that makes it much easier to output html and non-php code as well as php code.

Edited May 17, 2022 by ginerjm

[Revolutsio]

I only want to show the two divs if there is something in the platform2

I have run the code the way you said but get the same result with == & <>

[ginerjm]

Show me your new code .

And what are the "two divs"?  One choice is outputting a single incomplete div and the other is outputting 5 divs.

Edited May 17, 2022 by ginerjm

[Revolutsio]

So to give a bit of the story

it should only show the divs if there is text in the platform2 field. And not show if there is nothing in the field.

   if($game['platform2'] >"")
                echo "<div class='field-container')";
                else
                echo "<div class='title'>Platform</div>
                <div class='information'>{$game['platform2']}</div>
		        <div class='title'>Launcher</div>    
		        <div class='information'>{$game['launcher2']}</div>                
		        </div>";  
   ?>

Also could i put another div class='field-container' after the last div to add more later?

[ginerjm]

Ok - this code says to show the field-container div if your field is not empty.  And to show the 4 other divs if it is empty.  Plus you have an extra </div> tag in the else part that is not necessary.

PS - not a good idea to use the dash character in names, just use the underscore.

As for adding things, of course you can.  Just code them.

[dodgeitorelse3]

if I understand correctly this should work.

echo "<div class='field-container'>";
	
	if($game['platform2'] !== ""){
		echo "<div class='title'>Platform</div>    
		<div class='information'>{$game['platform2']}</div>
		<div class='title'>Launcher</div>    
		<div class='information'>{$game['launcher2']}</div>";
	}
	
echo "</div>";