need to make it so if a users is not logged in it displays a different message?

[runnerjp]

hey guys i have this

[/<?echo $auth[displayname] ?>code] but what do i add to this to display a different message if the user is not logged in like "guest"?

[Greaser9780]

I use sessions upon logging into my website. Then on my welcome page you can use an if statement to detect if there is a session for that user. If the user is logged in my pages display Welcome ".$_SESSION['username']."  If they are not logged in it can display either please log in or in your case you could have it say "Welcome Guest!

[runnerjp]

any chance u can put ur code on as an example for me to work with if thats ok ??

[desithugg]

<?

if($auth[displayname] == "")// if the variable is empty execute the fallowing

{

echo"Please login";

}

else

{

echo"Hey logged in as".$auth[displayname];

}

?>

[Greaser9780]

That'll work to. Might need single quotes around that displayname.

[desithugg]

oh yeah probably

<?

if($auth['displayname'] == "")// if the variable is empty execute the fallowing

{

echo"Please login";

}

else

{

echo"Hey logged in as".$auth['displayname'];

}

?>

[runnerjp]

thanks guys

[runnerjp]

ok that didnt work :(

[Greaser9780]

Can  you post a little more code  maybe from the query down to and including what you already posted?

[runnerjp]

fixed it!! took

 ['displayname'] 

and took the --> ' <-- out!!  thanks guys

[Greaser9780]

Wow, really. I always get errors when they're not in. Odd. Hey at least you got it though.

[Jessica]

You actually need to leave that in and then fix where it's originally set. What you're doing now is a poor coding practice. Read this:

http://us3.php.net/manual/en/language.types.array.php

 

Scroll down to :

Array do's and don'ts

Why is $foo[bar] wrong?