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Ch0cu3r

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Everything posted by Ch0cu3r

  1. Ch0cu3r
    PHP session can only shared with sub domains like subname.domain.com and domain.com. You cannot share session over different domains like domain1.com and domain2.com
  2. Ch0cu3r
    First notice message can be solved by checking to see if the HTTPS server exists $base_url = (isset($_SERVER['HTTPS']) ? 'https' : 'http') . '://' . $_SERVER['HTTP_HOST'] . '/'; Second error can solved with $keys = array_keys($path); $last = end($keys); // OR just $last = count($path) - 1;
  3. Ch0cu3r
    Look at edit below You are passing the new_package() method an undefined variable $new_package echo $manage->new_package($new_package); You cannot call new_package with an undefined variable. EDIT. Looking at the source for the new_package method it doest need anything passed to it. Change line 1245 in core-management to public function new_package() { Call new_package using echo $manage->new_package();
  4. Ch0cu3r
    Your code should be <?php if(isset($_POST['username']) && isset($_POST['password'])) { $username = mysql_real_escape_string($_POST['username']); $password = md5($_POST['password']); if (!empty($username) && !empty($password)) { $query = "SELECT `id` FROM `users` WHERE `username`='$username' AND `password`='$password'"; if ($query_run = mysql_query($query)) { if (mysql_num_rows($query_run) == 1) { $user_id = mysql_result($query_run,0,'id'); $_SESSION['user_id'] = $user_id; header('location: require.php'); } else { echo 'Invalid username or password'; } } else { echo 'Query error: ' . mysql_error(); exit; } } else { header("Location:jquery.php") ; } } ?> <!doctype html> <html> <head> <link type="text/css" rel="stylesheet" href="css.css"/> </head> <body> <div class="lol"> <h1 class="header">Thecatch</h1> <div id="header"></div> </div> <form action="<?php $current_file;?>" method="POST"> <div class="lol3">Email or Username<br/><input class="class1" type="text" name="username" size="19"> <label class="label" for="pass">Password</label> <input class="class2" type="password" name="password" size="19" > <input class="classname" type="submit" Value="LogIn"><br> <input class="check" type="checkbox" name="stay" value="Stay signed In"><p class="para7">Keep me logged in</p><br> </form></div> </body> </html>
  5. Ch0cu3r
    requinix did. Replace print_r ($value); with $string = $value->string; $string will be the data you want to serialize in the database?
  6. Ch0cu3r
    No, the public_html file is fine. This is most probably caused by an error. To see what the error could be either look at your servers error log or enable error reporting. Add these two lines after <?php to enable error reporting display_errors(1); error_reporting(E_ALL);What errors are shown?
  7. Ch0cu3r
    You cannot access the some_db() database method from outside of user class. You can only access that method from within the users class using $this->db->some_db(); The database object is stored within the $db property for the users class If you need to use the some_db() method outside of the users class. Then use the database object $myDB->some_db():
  8. Ch0cu3r
    Your code is fine. But are you are calling session_start at the top of the page that uses $_SESSIONS?
  9. Ch0cu3r
    If you're directly linking to secound.php in a hyperlink, like <a href="http://yoursite.com/secound.php">Link</a> then you cannot prevent direct access to that file, as you are linking directly to it. Are you only wanting to prevent access to secound.php if the user has not been to index.php first?
  10. Ch0cu3r
    Maybe debug_print_backtrace may help you?
  11. Ch0cu3r
    You cannot use set cookies after you have sent any output to the browser. Quote from php.net/setcookie
  12. Ch0cu3r
    When setting cookies you cannot access them immediately after. When you reload the page the cookie data will be available.
  13. Ch0cu3r
    I cant tell you that as I don't how the $data array is being populated.
  14. Ch0cu3r
    looking at the array structure for $data, The category is within a sub array called revision_post. You'll need to use $data['revision_post']['category'][0]
  15. Ch0cu3r
    That code above is to replace this code in log.php $login=login($username,$password); if($login===false){ //$error[]= echo "That username and password combination is incorrect"; } else { // set username session // redirect user to home //die($login); $_SESSION['user_id']=$login; header('location:index.php'); exit(); } Replace // successfully logged in! with the code you want to run when user successfully logs in Replace // did not successfully login with the code you want to run when the user does not successfully login. You can remove printf('<pre>%s</pre>', print_r($_SESSION, true));. it is only there to display what is stored within the $_SESSION variable when login is successful. The code in reply #9 replaces the code in init.php
  16. Ch0cu3r
    The logged_in function should work as before, no need to modify it. No need to use the user_data function as data is already in the $_SESSION variable Do not use $user_data, use $_SESSION init.php should be if(logged_in() === true) { $session_user_id = $_SESSION['user_id']; if(user_active($_SESION['username']) === false){ session_destroy(); header('Location:index.php'); exit(); } } how Is the password changed?
  17. Ch0cu3r
    This is nothing to do with PHP. There is most probably a .htaccess file some where that has mod_rewrite rules defined so site.com/filename.drac actually calls site.com/index.php?drac=filename. Somewhere in your code the modules() function from include.php is called so modes/filename.php is included.
  18. Ch0cu3r
    You could do $array = array(5 => 'first', 3 => 'first', 2 => 'secound', 4 => 'secound'); $array_values = array_unique(array_values($array)); printf('<pre>%s</pre>', print_r($array_values, true)); foreach($array_values as $value) { echo $value .' = ' . array_sum(array_keys($array, $value)) . '<br />'; }
  19. Ch0cu3r
    You do not need the user_data() function any more. This has now been merged with the login() function. The login function stores the users data in the $_SESSION. Instead of using the $user_data variable to get the users data you now use $_SESSION. When you want to echo the users name, you use <?php echo $_SESSION['name'];?> Instead of $user_data['name']
  20. Ch0cu3r
    make sure status.php is in the same folder as index.php. What url are you using to view status.php and what url are using to view index.php?
  21. Ch0cu3r
    Try looking to see what is stored within the whole of $_SESSION variable printf('<pre>%s</pre>', print_r($_SESSION, true)); If the product info is not in the session then your shopping cart is most likely storing the products information within the database. The $_SESSION['pdf_quote']['id'] varibale could hold the product id, This is used in database query to get the products information. You will want to look at your shopping carts documentation on how it stores and retrieves products in the database.
  22. Ch0cu3r
    What specific data do you need from that array? What are you trying to do?
  23. Ch0cu3r
    Maybe the following article may help http://shiflett.org/articles/how-to-avoid-page-has-expired-warnings
  24. Ch0cu3r
    Do you want to see what is stored in these arrays? You can use print_r for that printf('<pre>%s</pre>', print_r($_SESSION['pdf_quote'], true));
  25. Ch0cu3r
    You should not rely on the browsers back button to allow users to re-edit forms. You should provide a way for the user to go back and edit the forms so they are pre populated with the data they entered, or if you want the user to go back a page, then provide a link/button to that page or you could redirect the user with header() for an automatic redirect. If you need to clear a form you should use the forms reset button, not the browsers refresh button.
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