JAY6390

Not sure how you are getting the extra () unless something has been added, I get Ore-tachi ni Tsubasa wa Nai - 01

$subject = '[sHiN-Remux][MSPN-SUBS] Ore-tachi ni Tsubasa wa Nai - 01 [1280x720 h.264 AAC][FB36073E].mkv'; $result = trim(preg_replace('/(\[[^\]]+\]|\.mkv)/i', '', $subject)); echo $result;

preg_replace('~\bhttp://~i', '', $url);

it's easier to use parse_url

no problem

Oops you need to escape the escape character twice, like so /'(.*?)(?<!\\\\)'/

/'(.*?)(?<!\\)'/

Are you just wanting to list all matches that do? Or are you wanting to replace them with just one of that character, something like this $result = preg_replace('/([a-z])\1{2,}/i', '$1', $subject); Note that this is case insensitive

put a - before the \d That should do it

That's javascript not PHP The likely change you will need to make is to change parseInt($('#minimum_hours_charge').val())<0 so that 0 is 1

Your best option would be to explode() the string then use array_search to check for both values $arr = explode(' ', $string); if(in_array('567', $arr) && in_array('777', $arr)) { // TRUE } else { // FALSE }

Also note the $$text should be $text (ie the two $$ was a typo) - I tried to edit but the time limit expired apparently, so hopefully you don't have the same as me if it's working

No problem

$text = preg_replace('/\b([A-Z0-9._%+-]+@[A-Z0-9.-]+)(\.)([A-Z]{2,4}\b)/i', '$1 dot $3', $$text);

Be sure to set your session variables before redirecting

$result = preg_replace('/(\b[a-z])[a-z]+\s?/i', '$1', $subject);

You need a + after [0-9]

preg_match_all('/onclick="return false;">(.*?)<\/a>/',$data,$matches);

preg_match_all('/<a href="javascript:void(0);" onclick="return false;">.*?</a>/s',$data,$matches);

no problem

Try this $string = preg_replace_callback('/(ht|f)tps?:\/\/\S+/', 'trim_urls_callback', $string);

can you post some sample data

try \b instead of \s at the end

This is in the wrong forum, it should be in the main PHP forum not the regex one..

Yup. No problem