[SOLVED] Maths

[Allan-]

I have to check that $number1 is divisible by $number2. How?

When its on divisible, then I have to display the answer in fraction. If I have to divide 9 / 21, I have to disaplay it as a fraction, then how can I find the same multipliers they have (in this case they both are divisible by 3) and make the numbers of the fraction small as possible.

 

I hope that you understand my problem

[kenrbnsn]

This sounds like a homework assignment. We don't do homework assignments here.

 

Ken

[The Little Guy]

function divisibility($num1, $num2){
switch($num1){
	case 9:
		$total = $num1 + $num2;
		return $total % 9;
	break;
}
}

echo divisibility(9,21);

 

http://mathforum.org/k12/mathtips/division.tips.html

[BlueSkyIS]

This sounds like a homework assignment. We don't do homework assignments here.

 

Ken

 

until now.

[sasa]

try

<?php
function gcd($a,$b){
while ($c = $a % $b){
	$a = $b;
	$b = $c;
}
return $b;
}

echo gcd(4,6);
?>

 

[Maq]

I have to check that $number1 is divisible by $number2. How?

 

fmod ($dividend ,$divisor);

 

Returns the remainder, if 0, it's obviously divisible.

[Allan-]

its not homework, but i'll make this on my own.

at least i'll try.

[Maq]

Have you got it to work, or at least attempted to solve this?  If so, post your code again...