Handling an HTML form

[sahlahmin]

Not sure why the PHP variables in the code below aren't interpreting the values that they should be receiving from the HTML form.

 

HTML form

<form action="handle_form.php" method="post">

<fieldset><legend>Enter your information in the form below</legend>

<p><b>Name:</b> <input type="text" name="name" size="20" maxlength="40" /></p>
<p><b>Email Address:</b> <input type="text" name="email" size="40" maxlength="60" /></p>
<p><b>Gender:</b> <input type="radio" name="gender" value="M" /> Male <input type="radio" name="gender" value="F" /> Female</p>

<p><b>Age:</b>

<select name="age">
<option value="0-29">Under 30</option>
    <option value="30-60">Between 30 and 60</option>
    <option value="60+">Over 60</option>
</select>
</p>

<p><b>Comments:</b> <textarea name="comments" rows="3" cols="40"></textarea></p>
</fieldset>

<div align="center"><input type="submit" name="submit" value="Sumbit My Information"  /></div>
</form>

 

PHP handle_form

<?php #Script 2.2 handle_form.php

$name = $_REQUEST['name'];
$email = $_REQUEST['email'];
$comments = $_REQUEST['comments'];

echo "<p>Thank you, <b>$name</b>,
for the following comments:<br />
<tt>$comments</tt></p>
<p> We will reply to you at <i>$email</i>.</p>";

?>

 

[Pikachu2000]

What actually is happening, then? Anything? Nothing? Any error messages?

[sahlahmin]

when submitting information from the HTML form , the echo function is printing part of the message literally, and then just not the rest, like this...

 

Thank you, $name, for the following comments:

$comments

 

We will reply to you at $email.

"; ?>

[chintansshah]

Please replace with below code

 

echo "<p>Thank you, <b>".$name."</b>,

for the following comments:<br />

<tt>".$comments."</tt></p>

<p> We will reply to you at <i>".$email."</i>.</p>";

 

I used string concatenation. 

[Pikachu2000]

The concatenated code is functionally no different from what is posted in the OP. Concatenating it like that is pointless.

 

If the code posted in the OP directly copied/pasted from the script? If so, make a new file, and put the following in it, pick a name and save it, then call it into your browser.

<?php
phpinfo();
?>

 

If it isn't a direct copy, please copy/paste the actual the code here.

[sahlahmin]

where would phpinfo(); fit within the php tags of the code that i posted? can you post an example of what your talking about? I'm pretty new to php.

[Pikachu2000]

It doesn't go in the existing file, it goes in a new file. Save it as phpinfo.php, then call it into your browser as you would any other php script.

[phpfreak]

Also try using $_POST instead of $_REQUEST

[kenrbnsn]

How are you invoking the HTML file which contains the form?

 

Ken

[sahlahmin]

kenrbnson, I think this is the line your talking about...

 

<form action="handle_form.php" method="post">

 

its the only line in either document that links the two scripts together, other then them being in the same folder.

 

phpfreaks, I tried $_POST, same results

[sahlahmin]

Ok guys, I figured out what the problem was. I guess I wasn't previewing the page through a URL, and using the preview in Firefox method in Dreamweaver.

 

Thanks again everyone for your time.