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Hello, 

 

I want to select all records in php code with mysql database. I have a table called "Customer", it has 2 fields "Name", "Number"

How to select all records ?

 

If I write 

select * from customer;

It does not return me anything

 

 

 

If I write 

select name,number from customer;

It does return all records. 

 

Can some one tell me what to do here.............. :happy-04:

 

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<?php

$username = "*******";

$password = "*******";

$hostname = "*******";

$database = "*******";;

 

$conn = mysql_connect($hostname, $username, $password, $database) or die("Could not connect: ".mysql_error());

 

if ($conn) {

echo ("Connection is success<br>");

} else {

echo ("Connection is failed");

}

 

$selected = mysql_select_db("*****",$conn) or die("Could not select database");

 

if ($selected) {

echo ("Connection is success to database<br><br>");

} else {

echo ("Connection is failed");

}

 

$result = mysql_query("SELECT * from student");

 

//fetch tha data from the database

while ($row = mysql_fetch_array($result)) {

   echo "Name: " . $row{'name'} . ":::::Class:" .$row{'class'}. ":::::Number:" .$row{'number'} . "<br>";

}

 

?>

----------------------------------------------------------------------------------------------------------------------------------------------------------------

After executing the code in PHP, I get no records display on my php page, I hope you are able to understand that the code I have written over here, Thanks for replying...........
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  • Solution

echo "Name: " . $row{'name'} . ":::::Class:" .$row{'class'}. ":::::Number:" .$row{'number'} . "<br>";

Please use


tags when posting your code. Also I moved your topic as you posted in the MS SQL server forum, which is not what you are using.

 

The way you access an array element is using square-brackets ([]), not curly's ({}) so the above line should be:

   echo "Name: " . $row['name'] . ":::::Class:" .$row['class']. ":::::Number:" .$row['number'] . "<br>";
Lastly, add error checking to your query so you can see if it is failing or not:

$result = mysql_query("SELECT * from student");
if (!$result){
   die('Could not run query: '.mysql_error());
}
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