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Hi, I am trying to get the rank of a user in a database, based on his score, so when the user logs in he can see his rank. I am using this to build a list of all users ordered by their score for a different section.

$stmt = $dbh->query("SELECT * FROM $table ORDER BY score DESC"); 
 
    $rank = 0;
        while($uid = $stmt->fetchObject()) {
          $rank++;
          echo $uid->uname ."is ranked". $rank;
        };

How can I get ONLY a users rank in the db based on his ID number, if I have a table like, .

 

| user | ID | score |

Jim  | 2568 | 80

Pete | 5693 | 115

Sam | 3258 | 569

George | 7412 | 30

 

the ID numbers are a unique key

 

If Jim logs in today he will see:

 

Your Current Rank is 3

 

I am using PHP with PDO on a MySQL table. Thanks!

Edited by mediabob

Get the user's current score and count how many people have a score above that.

 

So using your idea, I have done this, and it works exactly for what I want, is this the best recommended way?

 

 

$stmt = $dbh->query("SELECT COUNT(uid) AS `rank` FROM $table WHERE score > ( SELECT score from $table WHERE uid = $uid )");
$result = $stmt->fetchColumn();
 
echo $result+1;
 

Or....try to use ALL SQL operator instead to add +1 and everytime to assign new $uid.

 

No....it's the same, b/s we have single output.

SELECT COUNT(*) AS `rank` FROM $table WHERE $table.score >= ALL ( SELECT $table.score FROM $table WHERE $table.id=$userID)
Edited by jazzman1

 

Fred    99
Joe     90
Mary    80
Jane    80
Paul    80
Peter   80
Jazzman 80

Jazzman,

if you use >= then your rank is now 7 instead of 3=

Edited by Barand
Fred    99
Joe     90
Mary    80
Jane    80
Paul    80
Peter   80
Jazzman 80
Barand  70

Jazzman,

if you use >= then your rank is now 7 instead of 3=

 

 

Yes, master, got it....but what about the user with lowest rank named "Barand" :happy-04:

 

If I run next query, "Barand" is getting rang 8 instead 4.

SELECT COUNT(*)+1 as 'rank'  FROM mydb.users WHERE score > (
SELECT score FROM mydb.users WHERE users.UserID=
Edited by jazzman1
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