Jump to content

Search the Community

Showing results for tags 'mysqli'.



More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • Welcome to PHP Freaks
    • Announcements
    • Introductions
  • PHP Coding
    • PHP Coding Help
    • Regex Help
    • Third Party Scripts
    • FAQ/Code Snippet Repository
  • SQL / Database
    • MySQL Help
    • PostgreSQL
    • Microsoft SQL - MSSQL
    • Other RDBMS and SQL dialects
  • Client Side
    • HTML Help
    • CSS Help
    • Javascript Help
    • Other
  • Applications and Frameworks
    • Applications
    • Frameworks
    • Other Libraries
  • Web Server Administration
    • PHP Installation and Configuration
    • Linux
    • Apache HTTP Server
    • Microsoft IIS
    • Other Web Server Software
  • Other
    • Application Design
    • Other Programming Languages
    • Editor Help (Dreamweaver, Zend, etc)
    • Website Critique
    • Beta Test Your Stuff!
  • Freelance, Contracts, Employment, etc.
    • Services Offered
    • Job Offerings
  • General Discussion
    • PHPFreaks.com Website Feedback
    • Miscellaneous

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Age


Donation Link

Found 52 results

  1. Hi All, I need to get a small function working for a site I need to build for a group of friends. I was able to get a login page, and a way to add data to the data base. Now I am stuck on the search and show results fuctionalities. I have found tens of scripts on the internet, but most of them are outdated, or I cant get them to work, either it sends me back a blank page, does nothing or sends me to an error page The GOAL User Inputs text in a text box, clicks submit, the data in the text box is looked for in the second collumn of the DB, The information of the collumns 2 to 7 of the DB for the name search are displayed either on the same page or on a new page. Is there any chance you could hel me with that, taken into account that I dont need the html part of the code, I only need help with the php part... Thanks in advance to all the people reading this and the ones helping me...
  2. I've written a script to store images in my database. The images have a caption that is also uploaded and stored. This was fairly easy to get working. I have a jquery function setup to add a new file input and caption input every time I click a button. This also works. What is not working is my PHP is not uploading multiple files for some reason. Could someone tell me what I have done wrong? Thanks HTML: <form id="uploadMultiple" method="post" action="/scripts/php/imageUploadTest" enctype="multipart/form-data"> <table class="fileUploadTable" id="uploadArea" cellspacing="0"> <tr> <td> <label for="imageFile">Image:</label> <input type="file" name="imageFile" accept=".jpg,.jpeg,.png,.gif"> </td> <td> <label for="imageCaption">Image Caption:</label> <input type="text" name="imageCaption"> </td> <td width="150px"> </td> </tr> <tr id="uploadSubmission"> <td> <input type="submit" value="Upload More" id="uploadMore"> </td> <td> <input type="submit" value="Submit" name="addImage"> </td> <td width="150px"> </td> </tr> </table> </form> JQuery for adding new elements: $(function() { var scntDiv = $('#uploadArea'); var i = $('#p_scents tr td').size() + 1; $('#uploadMore').live('click', function() { $('<tr><td><label for="imageFile">Image:</label> <input type="file" name="imageFile" accept=".jpg,.jpeg,.png,.gif"></td><td><label for="imageCaption">Image Caption:</label> <input type="text" name="imageCaption"></td><td><a href="#" class="removeUpload" width="150px" style="text-align: center">Remove</a></td></tr>').insertBefore( $('#uploadSubmission') ); i++; return false; }); $('.removeUpload').live('click', function() { if( i > 1 ) { $(this).parents('tr').remove(); i--; } return false; }); }); And finally the PHP: require($_SERVER['DOCUMENT_ROOT'].'/settings/globalVariables.php'); require($_SERVER['DOCUMENT_ROOT'].'/settings/mysqli_connect.php'); $db_name = 'imageUploads'; $tbl_name = 'gallery'; if(!$conn) { die('Could not connect: ' . mysqli_error()); } mysqli_select_db($conn, "$db_name")or die("cannot select DB"); foreach($_FILES['imageFile'] as $file){ $caption = $_POST['imageCaption']; $uploadDir = 'http://www.example.com/images/'.'gallery/'; $fileName = $_FILES['imageFile']['name']; $filePath = $uploadDir . $fileName; if(move_uploaded_file($_FILES["imageFile"]["tmp_name"],$_SERVER['DOCUMENT_ROOT']."/images/gallery/".$_FILES["imageFile"]["name"])) { $query_image = "INSERT INTO $tbl_name(filename,path,caption) VALUES ('$fileName','$uploadDir','$caption')"; if(mysqli_query($conn, $query_image)) { echo "Stored in: " . "gallery/" . $_FILES["imageFile"]["name"]; } else { echo 'File name not stored in database'; } } } I was hoping I had it working properly for multiple images with my `foreach` loop but it only uploads one image even if I have 4 selected. EDIT: I've tried modifying my code to this and it's not working either but looking at tutorials this seems to be more on the right track than my previous code: r equire($_SERVER['DOCUMENT_ROOT'].'/settings/globalVariables.php'); require($_SERVER['DOCUMENT_ROOT'].'/settings/mysqli_connect.php'); $db_name = 'imageUploads'; $tbl_name = 'gallery'; if(!$conn) { die('Could not connect: ' . mysqli_error()); } mysqli_select_db($conn, "$db_name")or die("cannot select DB"); foreach($_FILES['imageFile'] as $key => $name){ $caption = $_POST['imageCaption']; $uploadDir = 'http://www.example.com/images/'.'gallery/'; $fileName = $key.$_FILES['imageFile']['name'][$key]; $file_size = $_FILES['files']['size'][$key]; $file_tmp = $_FILES['files']['tmp_name'][$key]; $file_type= $_FILES['files']['type'][$key]; $filePath = $uploadDir . $fileName; if(move_uploaded_file($file_tmp,$_SERVER['DOCUMENT_ROOT']."/images/gallery/".$fileName)) { $query_image = "INSERT INTO $tbl_name(filename,path,caption) VALUES ('$fileName','$uploadDir','$caption')"; if(mysqli_query($conn, $query_image)) { echo "Stored in: " . "gallery/" . $_FILES["imageFile"]["name"]; } else { echo 'File name not stored in database'; } } } I've also added `[]` in the names of the HTML input elements that needed them.
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.