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Showing results for tags 'facebook'.
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please if i share or post a link to my website on facebook, and everyone who wants to download your report has to share the same link on his own wall to download the report and visitors coming from that link also have to do the same. How can i do this with a code? Thanks.
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Say I want to allow users to chat with each other either through text or video on my site, what would be the best way to go on about doing that? I know basic text chat system can be created with PHP/Mysql/Ajax. What about video chat? Or is there a chat plugin/service out there that I can use to implement in my site? Note that I am looking for something can allow thousands of registered users to chat with each other at the same time.
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Hello guys, i have implemebted facebook login for my website. However, tring to store the data into my local db seems to be a problem. I'll need a little assistance with the coding. Thanks in advance. BELOW IS THE ERROR MESSAGE I GET Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/xxxx/public_html/3rd_party/fbOAuth/functions.php on line 16 Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, null given in /home/xxxx/public_html/3rd_party/fbOAuth/functions.php on line 17 Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/xxxx/public_html/3rd_party/fbOAuth/functions.php on line 20 MY CODE <?php //require 'dbconfig.php'; $DBhost = "localhost"; $DBuser = "xxxx"; $DBpass = "xxxx"; $DBname = "xxxx"; $DBcon = new MySQLi($DBhost,$DBuser,$DBpass,$DBname); if ($DBcon->connect_errno) { die("ERROR : -> ".$DBcon->connect_error); } function checkuser($fbid,$fbfullname,$femail){ LINE 16: $check = mysqli_query("select from Users where Fuid='$fbid'"); LINE 17: $check = mysqli_num_rows($check); if (empty($check)) { // if new user . Insert a new record $query = "INSERT INTO Users (Fuid,Ffname,Femail) VALUES ('$fbid','$fbfullname','$femail')"; mysqli_query($query); } else { // If Returned user . update the user record $query = "UPDATE Users SET Ffname='$fbfullname', Femail='$femail' where Fbid='$fuid'"; LINE 20: mysqli_query($query); } }?> I'll be grateful for all the help i can get.
