[SOLVED] + or - 5

[nezbo]

hi all

 

i am looking for a function that will give me the numbers + or - 5 from a given number

 

e.g.

 

if ($number +- 5)

    This runs it the number is + or - 5

 

 

Hope this makes sense...

 

Neil

 

 

[trq]

Then you will need to write it. Theres no such function.

[nezbo]

Then you will need to write it. Theres no such function.

 

Cheers,

 

What is the best way to do this?

 

[genericnumber1]

edit: what he said

[Mark Baker]

Hope this makes sense...

Not really

 

if ($number +- 5)

    This runs it the number is + or - 5

This isn't even a function, you're trying to invent a new operator (+-)

But what are you actually comparing $number with? are you trying to say that $number must have a value of -5 or +5, or that it must be +/-5 from a second value?

 

 

[Adam]

Think he's trying to determine if it's positive or negative? ???

 

If that's the case you don't need to use some special operator, would just be:

 

if ($num == -5) {
    print 'Negative!';
} elseif ($num == 5) {
    print 'Positive!';
}

 

Please explain a little further what it is you're trying to achieve..

 

A

[ILMV]

No, what I think he wants is a function to return a list of numbers between his given number, and either + or - 5 numbers.

 

So for example,

 

getNumsBetween(23,5,'-')

19,20,21,22,23 // Would return

 

getNumsBetween(23,5,'+')

23,24,25,26,27 // Would return

 

Am I right?

 

ILMV

[nezbo]

sorry i will try and explaing a bit more

 

i want to get all the numbers 5 greater and 5 less than a given number

 

I.e. if I have a number 9  the if statement will only allow run if it is 4,5,6,7,8,9,10,11,12,13,14 etc...

 

 

 

Think he's trying to determine if it's positive or negative? ???

 

If that's the case you don't need to use some special operator, would just be:

 

if ($num == -5) {
    print 'Negative!';
} elseif ($num == 5) {
    print 'Positive!';
}

 

Please explain a little further what it is you're trying to achieve..

 

A

[nezbo]

you got it

 

No, what I think he wants is a function to return a list of numbers between his given number, and either + or - 5 numbers.

 

So for example,

 

getNumsBetween(23,5,'-')

19,20,21,22,23 // Would return

 

getNumsBetween(23,5,'+')

23,24,25,26,27 // Would return

 

Am I right?

 

ILMV

[Adam]

$num = 10;

for ($i = ($num - 5); $i <= ($num + 5); $i++) {
    print $i . ' ';
}

 

Not tested but should work ..

 

A

[trq]

function getnumbersaround($num, $diff=5) {
  return range($num-$diff, $num+$diff);
}

[lokie538]

Damn there's some talented coders here!!

[aschk]

As a side note: I have generated a function that will tell you if the $num is within a range.

 

/**
* Within function.
*
*/
function within($num, $range = array()){
if(!$count = count($range)){
	return false;
}
sort($range);
return ($num >= $range[0] AND $num <= $range[$count-1]);
}

/**
* EXAMPLE USAGE: constants
*/
if( within( 5, range( 3, 7) ) ){
  echo "true";
} else {
  echo "false";
}


/**
* EXAMPLE USAGE: variables
*/
$x = 5;
$y = $x -5;
$z = $x + 5;
if( within( $x, range( $y, $z) ) ){
  echo "true";
} else {
  echo "false";
}

 

Hopefully this will help someone.

[Mark Baker]

As a side note: I have generated a function that will tell you if the $num is within a range.

As a further side note, this already exists:

if (array_search(5, range( 3, 7))) {
  echo "true";
} else {
  echo "false";
}