Jessica

Please use google, thanks.

Try just: <script language="text/javascript"> alert("<?php echo "Alert Message";?>"); </script>

Just put 1 instead of ?. Your method is superfluous. Also, it's FROM, not FORM.

Oh sweet.

Exactly. But since you're replacing a letter (a) with 31, a turns into 8947 not 31

OH - you're replacing the strings with numbers - and then replacing numbers with other numbers. So it replaces the 3 in 31 with the new number for 3. See? I bet if you use my for loop instead of str_replace, it will work. Because it won't go back over the ones you've already replaced.

*sheepish* I use PHP5 but I don't know about autoload...heading the manual

That actually made me lol. For Realz.

If you shorten which array?

you can decode it. You removed them, and it still came up wrong? But it worked for me when I didn't have them.

My husband made a face.

Here is another attempt. This works. <?php <? $encoder = array('a'=>'31','b'=>'58','c'=>'17','d'=>'93','e'=>'40'); $str = 'abcdeabcde'; print $str.'<br />'; $newStr = ''; for($i=0; $i<strlen($str); $i++){ $newStr .= $encoder[$str{$i}]; } print $newStr; ?> http://grady.us/temp/test.php

I don't get it. I wonder if it's one of your special characters? What happens if you take them out? And then add them back in one by one and check if it screws up?

Wii <3.

Okay I'm a bit creeped out. But I like the monkeys idea. I'd use a CMS to do it. Of course, I wouldn't buy 60 domains without having an idea of what I was going to do with them first

Ah I see.

That is weird. When I use simpler code such as: <?php $encodeTxtArr = range('a', 'z'); $encodeNumArr = range(1,26); print str_replace($encodeTxtArr,$encodeNumArr,'a'); ?> It prints 1 Here is the code I wrote: <?php $encodeTxtArr = array_merge(range('a', 'z'), range('A','Z'), array('!', '@', '[', ']', '(', ')', '.')); $encodeNumArr = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70); $str = 'Hello this is a test. This sentence (which is long) has some special characters like [] and @!'; print $str.'<br />'; print str_replace($encodeTxtArr,$encodeNumArr,$str); ?> Just rearrange the numbers to whatever values you want, add the rest of your special chars, and see how that works? Here it is on my site: http://grady.us/temp/test.php

why do you add .mysql?

Why are you even using preg replace for this? You're trying to replace one character with a number. Use str_replace.

This much time. And hard.

if(isset($var1) && isset($var2)) or the way syntax posted. Yes, the way you did is wrong, it should have given you an error Turn on error reporting.

No, nevermind. Sorry.

Why would it be hard for them to use? I've given clients FTP access to their own folder on my server before.

Why don't you use FTP to upload them, and then run a php script to loop through the directory and resize?

Textpad