PravinS
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Everything posted by PravinS
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you can use PHP time zone instead of javascript time zone
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remove the back ticks (``) from VALUES of INSERT query and use single quotes (' ') $query = "INSERT INTO user(user,pass,priv,mail,avatar,date) VALUES('$user','$pass','$priv','$mail','$avatar','$date')"; may this works for you
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check the SQL query, whose resource id is passed to mysql_fetch_array() function at mentioned line or else show us the code of C:\xampp\htdocs\index.php
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use this updated javascript function function checkForm() { var obj = document.getElementsByName('dest[]'); var destCount = obj.length; var destSel = false; for(var i = 0; i < destCount; i++) { if(obj[i].checked == true) destSel = true; } if(destSel == false) { alert('Select one or more destinations'); } return destSel; }
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use this code <html> <head> <script language="javascript"> function checkForm(){ var obj = document.getElementsByName('dest[]'); var destCount = obj.length; var destSel = false; for(i = 0; i < destCount; i++){ if(obj.checked == false){ destSel = true; break; } } if(!destSel){ alert('Select one or more destinations'); } return destSel; } </script> </head> <body> Select at least one destination <form action="" method="post"> <input id="cx" type="checkbox" name="dest[]" value="CX" /> <label for="cx">Cox's Bazar</label><br /> <input id="su" type="checkbox" name="dest[]" value="SU" /> <label for="su">Sundarban</label><br /> <input id="sy" type="checkbox" name="dest[]" value="SY" /> <label for="sy">Sylhet</label><br /> <input id="ch" type="checkbox" name="dest[]" value="CH" /> <label for="ch">Chittagong</label><br /> <br /> <input type="submit" name="Go" value=" Go " onclick="return checkForm();"/> </form> </body> </html> also check the jsfiddle
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Just remove onsubmit="return checkForm(this);" from form tag and add it to button as onclick="return checkForm(this);" Use this <form action="" method="post"> <input id="cx" type="checkbox" name="dest[]" value="CX" /> <label for="cx">Cox's Bazar</label><br /> <input id="su" type="checkbox" name="dest[]" value="SU" /> <label for="su">Sundarban</label><br /> <input id="sy" type="checkbox" name="dest[]" value="SY" /> <label for="sy">Sylhet</label><br /> <input id="ch" type="checkbox" name="dest[]" value="CH" /> <label for="ch">Chittagong</label><br /> <br /> <input type="submit" name="Go" value=" Go " onclick="return checkForm(this);"/> </form>
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your php code should be like this <?php // Always try to connect and select the DB before anything else $con = mysql_connect("localhost", "jingleko_reload", "*******") or die("Couldnt Connect to DB - ".mysql_error()); mysql_select_db("jingleko_reloader", $con) or die("Couldnt Select a DB - ".mysql_error()); // Set post var $Epost = trim(addslashes(strip_tags($_POST['Epost']))); if (isset($_POST['Epost'])) { // Look for it in DB $query = "SELECT Epost FROM newsletter WHERE Epost='".$Epost."'"; $result = mysql_query($query); //If found, do next thing if (mysql_num_rows($result) > 0) { mysql_query("DELETE FROM newsletter WHERE Epost='$Epost'") or die(mysql_error()); echo "<div align=\"center\"><img src=\"Pics/Vlaamse Leeuw.jpg\" width=\"114\" height=\"127\" border=\"0\"></div>"; echo "<p align=\"center\"><b>Thank you, you are now removed from the list.</b></p><br>"; echo "<p align=\"center\"><a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></p>"; } else { echo "<div align=\"center\"><b><font color=\"red\">This address does not exist</font></b></div><br>"; echo "<div align=\"center\"><a href=\"eruit.htm\"><img src=\"Pics/herbegin.gif\" width=\"95\" height=\"30\" border=\"0\"></a>"; echo "<a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></div>"; } } mysql_close($con); ?>
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you can use isset() function to check if $_FILES['image'] is set of not like if (isset($_FILES['image'])) { // your code here var_dump($_FILES['image']); // your code here } may this will help you
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you can check it like this if (is_array($_POST['interest']) && count($_POST['interest']) > 0) { // code here }
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do you know URL rewriting? check : http://httpd.apache.org/docs/2.0/misc/rewriteguide.html
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i think your code should be like this $event = array("Flash Flood Watch", "Flash Flood Warning", "Severe Thunderstorm Watch", "Severe Thunderstorm Warning", "Torndao Watch", "Torndao Warning"); $searchvalue = "Flash Flood Watch"; //as example if (in_array($searchvalue, $event)) { echo "Match found"; } also go through in_array() function properly http://www.php.net/in_array
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use php explode() function http://www.php.net/manual/en/function.explode.php
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give name as array for each field, as <?php foreach ($items as $item) { echo'<div class="items-row"> <label for="name_'.$item['item_id'].'">'.$item['item_name'].'</label> <div class="item_input"><input type="text" name="quantity[]" id="'.$item['item_name'].'" value="0"></div> <input type="hidden" name="item_ids[]" value="'.$item['item_id'].'"> <input type="hidden" name="user_ids[]" value="'.$moving_basics_id.'"> </div>'; } ?>
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your function should return the value like <?php function test() { $response = "hello"; return $response; } ?> and then you can call the function like this <input type="textbox" name="xx" value="<?php echo test(); ?>" />
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can you show us the actual code
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it means you haven't created database on your local machine or the database connection in database.php is not correct
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at this line add mysql_error() like this and check what is the issue $data=mysql_query("SELECT OT.nostaf, OT.otl_tkh_m, OT.otl_tkh_y ,OT.otl_jum_jam, OT.otl_jabatan FROM ot_line OT") or die(mysql_error());
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mysql_select_db("ahamdabad_vpn_ip$", $dbc); $sql = "select main_system from ahamdabad_vpn_ip$"; "ahamdabad_vpn_ip$" is you database or table name? also it is not good practice to use "$" in database of table name
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use urlencode() and urldecode() functions
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echo the SQL query and execute it in phpmyadmin also write mysql_close($con); at the end the bottom of the code
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check you SQL query, remove space between FROM and table name from SQL query $query ="SELECT * From Section order by sectCode ASC";
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your form method is post, so use POST while getting variable data $destinationCode=$_POST['destinationcode']; $numberofadults=$_POST['numberofadults']; $numberofchildren=$_POST['numberofchildren']; $startdate=$_POST['stardate']; $enddate=$_POST['enddate'];
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you can check this example http://www.w3schools.com/php/php_ajax_database.asp
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try uncommenting the if condition <?php //$ab=1; $ab = ''; if(isset($_GET['id'])) $ab= $_GET['id']; echo $ab; ?>
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check http://www.phpclasses.org/package/5927-PHP-Display-an-hierarchic-menu-stored-in-a-MySQL-table.html