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Sandra

Help a newbie please :)

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Hello all, I'm a basic coder 😀
I want to insert a line break in this code, after the {hobby:value} it gives me : syntax error, unexpected '>'

if($_POST['form']['hobby'] == '')
  $modUserEmailText = str_replace('{hobby:caption} : {hobby:value}', ''<br/>'',$modUserEmailText);


{hobby:caption} : {hobby:value} are placeholders in the sent email, since there are several of them, all I want is a line break between each.. and must end with $modUserEmailText);
is this possible to do?

{hobby:caption} : {hobby:value}
{age:caption} : {age:value}
{book:caption} : {book:value}

Thanks a million!

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I take it you've seen " before but never typed it out until now?

That there is (supposed to be) a double quote, not two single quotes. Shift + '

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I have tried the single quote and the double quote, in different places... many many tests.. before I came asking for help :(

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Well, all I can really do is tell you about the problems you post here, and this current one is because you're typing two apostrophes in the place of one quotation mark.

If you still have problems after fixing that then we'll deal with them. But you'll have to describe them.

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:) if you guys had to put a line break in this code, how does it go?

cheers

if($_POST['form']['age'] != '') $modAdminEmailText .= '{age:caption}: {age:value}';

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I've tried this, still no change, but does not give me errors

if($_POST['form']['hobby'] != '')
echo "<br />";
$modUserEmailText .= '{hobby:caption} : {hobby:value}';

This one gives me an error : syntax error, unexpected ','

if($_POST['form']['hobby'] != '')
$modUserEmailText .= '{hobby:caption} : {hobby:value}'."\r\n";

any thoughts?

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7 hours ago, Sandra said:

This one gives me an error : syntax error, unexpected ','

if($_POST['form']['hobby'] != '')
$modUserEmailText .= '{hobby:caption} : {hobby:value}'."\r\n";

The error is complaining about a comma in the code. There is no comma in that code.

  • Haha 1

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Can you use the <> code icon to open up a window and then do a copy and paste from your editor into that code window so that we can see the real code you are running?  Not all of it - just the part you are questioning.

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With most of these examples you are omitting blocks.  Here is a block:

{
   //Something
}

Many languages use the {} to denote a block.  There are others that use something different, or use indentation (most notably python), but PHP is not one of those languages.

Let's go back to an example you gave (Indentation mine):

 

if($_POST['form']['hobby'] != '')
    echo "<br />";
    $modUserEmailText .= '{hobby:caption} : {hobby:value}';

After your condition

 ($_POST['form']['hobby'] != '')

You do not have a start block.  So only the next line will be executed if the condition is true.  I don't think that is what you expect.    So you need a block around ALL the code that will execute if the condition is true:

if($_POST['form']['hobby'] != '') {
    echo "<br />";
    $modUserEmailText .= '{hobby:caption} : {hobby:value}';
}

 

Obviously you are not giving us real code or are giving us snippets of the code as the errors don't correlate to the code you've provided, but perhaps this explanation will help you out.  Just for completeness:

if (!empty($_POST['form']['hobby']) {
    echo "<br />";
    $modUserEmailText .= '{hobby:caption} : {hobby:value}'    
}

This would be the proper way to handle the condition you are checking for.  The problem with the code you presented, is that it will provide a runtime error if the $_POST['form']['hobby'] element does not exist.  For things like checkboxes, this is a common occurrence.  empty checks that the variable exists (isset) AND that it has a value  (!= ''');  You might also want to trim the value, as even a space would pass through your check and empty.

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