Philip
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Everything posted by Philip
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I still am a fan of HTML-Kit Tools
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Well depending on the chip & how the heatsink is sitting on the chip, it might be time to reseat it using a better thermal grease. Also check to see if possible something is on the chip, as there might be some dust or dirt on the temp sensor - I've had that happen before. I know my GPUs run pretty hot (dual ATI's 4890) and I run the fans around 30% most of the time, but occasionally they will pop up to 100%.
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What card are you running & is it a default fan?
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I know about the same as both, if anything more phone numbers because you never know when your cell phone decides to give out and you don't have internet access
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Well what does the column "clicks" have as its value?
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Yeah. I think you're right. It has something to do with the serialization.... What are the values of $c1-5, is the POST field actually named the same value as the serialization?
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The line I posted.
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Missing semicolon: $result = ("SELECT * FROM village9 JOIN player9 ON village9.player = player9.id JOIN tribe9 ON player9.ally = tribe9.id WHERE tag = 'dns';")
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I think it'd be best if you posted sample data from each table and how you wanted it joined.
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Fatal error: Call to a member function fetchrow()
Philip replied to seany123's topic in PHP Coding Help
Either your query is failing, or your DB class isn't returning an object into $query0 -
You can use Google Analytics with it, and you can see what pages & content types are doing the best. I haven't personally used AdSense with GA, but I do use GA for a lot of my sites.
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At least they are being active on fixing things rather than just wait for one big update and have a bunch of holes until then. And I've only done single player on the PC, but I'm more than impressed
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if ($open_status = 'checked') { and if ($closed_status = 'checked') { both need a comparison operator == if ($open_status == 'checked') { and if ($closed_status == 'checked') {
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Take a look at the fputcsv function.
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[SOLVED] IF Statement & Two Tables With Different Echoes
Philip replied to EternalSorrow's topic in PHP Coding Help
... the code above was an example using the query I had. while ($row = mysql_fetch_array($result)) { extract($row); if (isset($table1) && $table1 == 'film') { echo '<li><a href="filmography.php?title='.$title.'"><img src="images/thumbnails/'.$image.'.jpg" alt="" title="'.$title.' ('.$year.')"></a></li>'; } if ((isset($table2) && $table2 == 'people') { echo '<li><a href="biography.php?name='.$name.'"><img src="images/thumbnails/'.$img.'.jpg" alt="" title="'.$name.' ('.$occupation.')"></a></li>'; } } -
[SOLVED] IF Statement & Two Tables With Different Echoes
Philip replied to EternalSorrow's topic in PHP Coding Help
Using the query above.... if($result['tableID'] == 'film') { echo 'film link'; } if($result['tableID'] == 'people') { echo 'people link'; } -
SLAM!!! New PHP version and now nothing works
Philip replied to jeffery1493's topic in Third Party Scripts
Open up /phpbb/includes/sessions.php and look at lines 1 & 2. That's sending your ouput. -
You could have him install WAMP on there, and run it in the background. But, if he turns off his computer, or kills the process - then you're outta luck.
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[SOLVED] IF Statement & Two Tables With Different Echoes
Philip replied to EternalSorrow's topic in PHP Coding Help
I'd recommend changing your query to only pull the data you need & an identifier: SELECT title, year, etc, 'film' as tableID FROM film UNION ALL SELECT title, year, etc, 'people' as tableID FROM people ORDER BY id DESC LIMIT 5 Then when calling the results: $result['tableID'] will give you the proper table. -
Help me to display mysql data in website like as i want!
Philip replied to GFXUniverse's topic in PHP Coding Help
Did you take a look at the source on the outputted page? You might spot the problem there -
If you're gathering from his DVR, the easiest way would be to to use a dynamic dns service. Since its from a stand alone DVR (and most likely not a PC), a cron job & using a pinging script on his side to your server with a password to gather the ip would probably be out of the question.
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"Doesn't work" doesn't help you solve your problem What errors are you getting (copy/paste them here)
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Well you changed the sql: $sql="INSERT INTO `my_db`.`my_table` ( `usrID` , `usrName` , `usrEmail` , `usrDatereg` ) VALUES ( NULL , '$Fname', '$eMail', '$date' )"; to sql="INSERT INTO 'mailing' ('usrName','usrEmail','usrDatereg') VALUES ($Fname,$eMail,$date)"; Which one is correct? Because I'd imagine the first one is failing because it isn't selecting the right database/table... and the second one because you're using single quotes where backticks would be appropriate (but not needed in this case) and missing single quotes where you need them - around the values. sql="INSERT INTO mailing (usrName,usrEmail,usrDatereg) VALUES ('$Fname','$eMail','$date')";
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Echo $sql & mysql_error() and see what those post. Also, sanitize your inputs, always!
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well you're really not missing much. And does anybody else have problems with staying connected?