Jump to content

Search the Community

Showing results for tags 'time'.



More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • Welcome to PHP Freaks
    • Announcements
    • Introductions
  • PHP Coding
    • PHP Coding Help
    • Regex Help
    • Third Party Scripts
    • FAQ/Code Snippet Repository
  • SQL / Database
    • MySQL Help
    • PostgreSQL
    • Microsoft SQL - MSSQL
    • Other RDBMS and SQL dialects
  • Client Side
    • HTML Help
    • CSS Help
    • Javascript Help
    • Other
  • Applications and Frameworks
    • Applications
    • Frameworks
    • Other Libraries
  • Web Server Administration
    • PHP Installation and Configuration
    • Linux
    • Apache HTTP Server
    • Microsoft IIS
    • Other Web Server Software
  • Other
    • Application Design
    • Other Programming Languages
    • Editor Help (Dreamweaver, Zend, etc)
    • Website Critique
    • Beta Test Your Stuff!
  • Freelance, Contracts, Employment, etc.
    • Services Offered
    • Job Offerings
  • General Discussion
    • PHPFreaks.com Website Feedback
    • Miscellaneous

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Age


Donation Link

Found 10 results

  1. I am working on a form with php generated values. What I have right now is as follows: <tr> <td><p>ENTRY TERM: <select name="entry_term" > <option value="">Choose One:</option> <?php $year=date("Y"); for ($y=0;$y<5;$y++) { echo '<option value="Fall '.($year+$y).'">Fall '.($year+$y).'</option>'; echo '<option value="Spring '.($year+$y+1).'">Spring '.($year+$y+1).'</option>'; } ?> </select> </p></td> This currently generates a list of : Fall 2014 Spring 2015 Fall 2015 Spring 2016 Fall 2016 ...etc for next 5 years What I need to do is have this time sensitive to exclude once a specific month has passed. For example once August 2014 has started "Fall 2014" should be excluded... or when Jan 2015 has started "Spring 2015" should be excluded. Can someone help me solve this as I am unsure of how to move forward with this. Thanks,
  2. I would really appreciate help and I hope my problem can be solved easily. I am attempting to display the date/time based on the user's location. I have installed the timezone.js plugin for help as well. Is there a way to convert the Jquery variable that displays the users timezone location and insert it inside the PHP date_default_timezone_set? If there is an easier way to display the users timezone date and time please let me know otherwise this was the only solution I could find. Thanks in advanced... Here is my code Header <header> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> <script src="Time/detect_timezone.js"></script> <script src="Time/jquery.detect_timezone.js"></script> <script> $(document).ready(function(){ $('#tzvalue').set_timezone({'default' : 'America/Los_Angeles'}); }); </script> </header> Currently I have: (the timezone currently appears in the text box and below the textbox PHP echos the current time in my timezone) <input type="text" Name="Timezone" id="tzvalue"></input> <?php date_default_timezone_set("America/Chicago"); echo "The time is " . date("h:i:sa"); ?> What I want is: <?php date_default_timezone_set("$tzvalue"); echo "The time is " . date("h:i:sa"); ?>
  3. Basically what I am trying to do is have an option of choosing an "expiry time" when inserting a record. I will then use that expiry time to make a countdown clock that will expire the record when reached 0; but that's the step after. Right now I am having a bit of issue inserting that expiry time into the database. Here is my code. The error i get in the option value is something like <option value="<b>Notice</b>: Undefined variable...">. <?php $date_added = date('Y-m-d H:i:s'); $expiry_1 = date('Y-m-d H:i:s', strtotime('$date_added + 1 hour')); $expiry_6 = date('Y-m-d H:i:s', strtotime('$date_added + 6 hours')); $expiry_12 = date('Y-m-d H:i:s', strtotime('$date_added + 12 hours')); ?> <fieldset> <label>Expiry Time</label> <select name="expiry_time"> <option value="0">Select Time</option> <option value="<?php echo $expiry_1; ?>">1 hour</option> <option value="<?php echo $expiry_6; ?>">6 hours</option> <option value="<?php echo $expiry_12; ?>">12 hours</option> </select> </fieldset>
  4. I am trying to subtract a submitted time from the total time. For example, user puts in a start time of 09:00 and end time of 17:00 This gives me a total hours of 08:00, which is correct. What I want to do is allow the user to put, for example, 02:30 into a third input and click calculate, which should give a total time of 05:30. Here is the code I have for calculating the difference between both times: <?php if(isset($_POST['start_shift1']) && $_POST['end_shift1'] && $_POST['break1'] != "") { $datetime1 = new DateTime($_POST['start_shift1']); $datetime2 = new DateTime($_POST['end_shift1']); $break = new DateTime($_POST['break1']); $mondiff = $datetime1->diff($datetime2); ?> <input type="text" readonly class="form-control" name="monday" value="<?php echo $mondiff->format('%H:%I'); ?>"> <?php } ?> Does anyone know how I can subtract $break from $mondiff?
  5. Ryanm353

    Date picker

    Hello, Basically ive got a html drop down list, with various options based on urgency. One of the options is "Can wait" and if the user selects this option I want them to be displayed with a date picker so that they can pick a date. Ive got a HTML5 date picker in the form but its displayed all the time, whereas im looking for it to be displayed only if the user picks "Can wait". Is there a method I could use to get that to work? I need to get this working and I have done research, but to no avail. Any help would be greatly appreciated. Thanks.
  6. Please Can someone help me on this Am creating a timetable system and i want to check only the time difference Am collect a time only from the html form thus $startTime = 13:30:00 $endTime = 14:00:00 How can i find the deference between this time from the html in php. Thanks
  7. I have users who signed up for an email list and there is a table of them and the join date is in unix timestamp. I do not care about the date, only the time they signed up. I am putting together code to be run on cron to decide who gets emailed. It will be run probably every hour. When it runs the first thing I need it to do is select all users who from the current time through the next hour registered. This way I can then email people around the time they initially joined my site. Here is what I have: //$input is the minutes range (which will be most likely an hour so this variable should be 60) function to_email($input) { require_once('dbconnect.php'); $cur_hours = date('H'); $cur_minutes = date('i'); $cur_seconds = ($cur_minutes + ($cur_hours * 60)) * 60; $end_seconds = $input * 60; $end_seconds = $cur_seconds + $end_seconds; $result = mysql_query("SELECT * FROM usertable WHERE " . $cur_seconds . " <= (HOUR(opt_time)*60*60) + (MINUTE(opt_time)*60) + SECOND(opt_time) AND '" . $end_seconds . " > (HOUR(opt_time)*60*60) + (MINUTE(opt_time)*60) + SECOND(opt_time)'"); $row = mysql_fetch_array($result); } The php part works as what I think is needed. But the query does not. I am not very good at MySQL queries so don't judge.
  8. Here is my countdown counter code. It works. But I would like to show multiple of these countdown counters with different dates, on a single page. I tried duplicating them and giving them different "due" id name but I the result I get is like this "NaNd NaNh NaNm NaNs". What's the proper way to duplicate the code below and give them different dates? <div id="due"></div> <script> // Set the date we're counting down to var countDownDate = new Date("2017-05-05 19:01:58c").getTime(); // Update the count down every 1 second var x = setInterval(function() { // Get todays date and time var now = new Date().getTime(); // Find the distance between now an the count down date var distance = countDownDate - now; // Time calculations for days, hours, minutes and seconds var days = Math.floor(distance / (1000 * 60 * 60 * 24)); var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60)); var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60)); var seconds = Math.floor((distance % (1000 * 60)) / 1000); // Display the result in the element with id="due" document.getElementById("due").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s "; // If the count down is finished, write some text if (distance < 0) { clearInterval(x); document.getElementById("due").innerHTML = "OVERDUE"; } }, 1000); </script>
  9. cobusbo

    Countdown timer

    Hi Im creating a countdown timer to show a result but I only want to show the result for x time then I want it to disappear, but seems like Somewhere I'm going wrong with my if functions any help... <html> <?php define('TIMEZONE', 'Africa/Harare'); date_default_timezone_set(TIMEZONE); $targetDate = new DateTime('2015-11-24 11:57:00'); $runningDate = new DateTime('2015-11-24 12:08:00'); $time = new DateTime(); $remaining = $targetDate->diff(new DateTime()); // not done if( $time < $targetDate ) { echo $remaining->format('%a D - %H:%I:%S'); //--> 86 D - 19:44:24 } // done elseif($targetDate < $runningDate ) { print "The time has been reached show this messagt till runningdate is reached"; } elseif($time > $runningDate ) { print ""; }else{ print ""; } ?> </html>
  10. honkmaster

    Date Time Difference Issue

    Hi, I have two date and time stamps stored in my database, I'm using the below script to calculate the difference but whenever I'm getting an extra 1 hour added ?? Any ideas, Cheers Chris <?php $start = $row_rsComplete['quote_added']; $finish = $row_rsComplete['quote_complete']; $difference = ($finish - $start); $day = round(($difference % 604800) / 86400); $hours = round((($difference % 604800) % 86400) / 3600); $minutes = round(((($difference % 604800) % 86400) % 3600) / 60); echo $day." days"."<br/>"; echo $hours." hours"."<br/>"; echo $minutes." minutes"."<br/>"; ?>
×

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.