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Found 8 results

  1. I have date stored in database in any of the given forms 2020-06-01, 2020-05-01 or 2019-04-01 I want to compare the old date with current date 2020-06-14 And the result should be in days. Any help please? PS: I want to do it on php side. but if its possible to do on database side (I am using myslq) please share both ways🙂
  2. On another forum I ran across someone with a problem I have never had to deal with and am interested in the solution for it. He has dates in varchar formatted as 12/25/2015 and wants to update so the date is formatted as a proper date (YYYY-MM-DD) with a date column type. Off the top of my head I was thinking, Create a new date type column Do an update on the dates to replace the slashes with dashes. UPDATE table SET baddate = REPLACE(baddate, '/', '-'); Then make a little script to query the bad dates in reverse twice and re-insert the data with a foreach to the correct date column. SELECT reverse(baddate) AS rev, (SELECT REVERSE(rev) FROM mytable) FROM mytable foreach ($result AS $row){ //Insert data to real date column } I am wondering what a 100% sql solution would be or any other ideas to deal with it.
  3. I've got an HTML 5 date input box working on my site. Anyone know how to make the whole thing selectable like a drop down (select) box? Currently you can only select it by clicking on the arrow at the far right of it. I don't mind about losing the cross or up and down arrows. I just want the field to be fully selectable like a drop down box. Any ideas please? Thanks.
  4. Hi All, I'm really hoping someone can help me as i'm sure there's quite a simple solution to this. I'm building a form in Wordpress using a form builder plugin. The form has several date fields that clients need to fill in to tell us when they will be sending us print files and then a 2nd set of fields for when they need to be sent back. I've found some code on the plugin devs website that shows me how to set the 2nd date to be XX number of days after the 1st date but it only works if you have 2 date fields in your form. I currently have about 40 so i need to know how to extend this code to include more date fields. Here is the code the plugin dev supplied: add_action('frm_date_field_js', 'start_and_end_dates', 10, 2); function start_and_end_dates($field_id, $options){ $key_one = 'pickup';// Change pickup to the KEY of the first date field $key_two = 'dropoff';// Change dropoff to the KEY of the second date field $days_between = 0;// Change 0 to the number of days that should be between the start and end dates if ( $field_id == 'field_'. $key_one ) { echo ',beforeShowDay: function(dateOne){var secondDate=$("#field_' . $key_two . '").datepicker("getDate");if(secondDate==null){return[true];}var modDate=new Date(secondDate);modDate.setDate(modDate.getDate()-' . $days_between . '+1);return [(dateOne < modDate)];}'; } else if ( $field_id == 'field_' . $key_two ) { echo ',beforeShowDay: function(dateTwo){var firstDate=$("#field_' . $key_one . '").datepicker("getDate");if(firstDate==null){return[true];}var modDate=new Date(firstDate);modDate.setDate(modDate.getDate() + ' . $days_between . '-1);return [(dateTwo > modDate)];}'; } else { echo ',beforeShowDay: null'; } } So in effect all i need to do is find out how to extend this to add more date fields. Any help would be amazing as i'm very new at this and know very little about coding. Thanks Chris
  5. Say I have a simple date like this. $date = 2017-08-10 00:06:10; I would like to have an if statement that tells me whether or not the date is empty. These are my methods but I'm not sure if it's the proper way of doing it. . if(empty($date)) { // do nothing } else { // do something } if($date == 0000-00-00 00:00:00) { // do nothing } else { // do something }
  6. Hi, I have two date and time stamps stored in my database, I'm using the below script to calculate the difference but whenever I'm getting an extra 1 hour added ?? Any ideas, Cheers Chris <?php $start = $row_rsComplete['quote_added']; $finish = $row_rsComplete['quote_complete']; $difference = ($finish - $start); $day = round(($difference % 604800) / 86400); $hours = round((($difference % 604800) % 86400) / 3600); $minutes = round(((($difference % 604800) % 86400) % 3600) / 60); echo $day." days"."<br/>"; echo $hours." hours"."<br/>"; echo $minutes." minutes"."<br/>"; ?>
  7. Hi Im creating a countdown timer to show a result but I only want to show the result for x time then I want it to disappear, but seems like Somewhere I'm going wrong with my if functions any help... <html> <?php define('TIMEZONE', 'Africa/Harare'); date_default_timezone_set(TIMEZONE); $targetDate = new DateTime('2015-11-24 11:57:00'); $runningDate = new DateTime('2015-11-24 12:08:00'); $time = new DateTime(); $remaining = $targetDate->diff(new DateTime()); // not done if( $time < $targetDate ) { echo $remaining->format('%a D - %H:%I:%S'); //--> 86 D - 19:44:24 } // done elseif($targetDate < $runningDate ) { print "The time has been reached show this messagt till runningdate is reached"; } elseif($time > $runningDate ) { print ""; }else{ print ""; } ?> </html>
  8. Here is my countdown counter code. It works. But I would like to show multiple of these countdown counters with different dates, on a single page. I tried duplicating them and giving them different "due" id name but I the result I get is like this "NaNd NaNh NaNm NaNs". What's the proper way to duplicate the code below and give them different dates? <div id="due"></div> <script> // Set the date we're counting down to var countDownDate = new Date("2017-05-05 19:01:58c").getTime(); // Update the count down every 1 second var x = setInterval(function() { // Get todays date and time var now = new Date().getTime(); // Find the distance between now an the count down date var distance = countDownDate - now; // Time calculations for days, hours, minutes and seconds var days = Math.floor(distance / (1000 * 60 * 60 * 24)); var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60)); var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60)); var seconds = Math.floor((distance % (1000 * 60)) / 1000); // Display the result in the element with id="due" document.getElementById("due").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s "; // If the count down is finished, write some text if (distance < 0) { clearInterval(x); document.getElementById("due").innerHTML = "OVERDUE"; } }, 1000); </script>
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