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Showing results for tags 'linux'.
Found 8 results
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Hi all ! Can someone please explain what the following command does:- sudo sed -i s,scotchbox.local,$DOMAIN,g /etc/apache2/sites-available/$DOMAIN.conf sudo sed -i s,/var/www/public,/var/www/$DOMAIN/public,g /etc/apache2/sites-available/$DOMAIN.conf I can across these commands in here. I have tried them out in the terminal as a modified example :- sudo sed -i, s,www,the,g test.txt. where test.txt has 2 lines of some text containing the word 'the' a couple of times. The command seems to do nothing. There is no change in test.txt. I cannot get any example of sed -i, s on google. In fact i cannot get a similar example of sed anywhere on google. But then i believe sed is extremely versatile and has tons of usages. Grateful for any help. Thanks all.
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good day dear php-freaks i need to rename files in _ one _ directory - more than 50 files are in this..folder: the files are named like so: 01 02 03 04 ... 49 50 each file has got a number as a file name. each file should get a character - like so: r01, r02, r03, r04 and so on . .... r50 how can we do this on commandline
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hello dear community I’m trying to capture the output of the top command into a file. When I execute top > output.txt, the output.txt file contains lot of junk characters. What is the best method to capture the output of the top command into a readable text file? i tried to use the top command batch mode operation option ( -b ) to capture the top command output into a file. top -n 1 -b > top-output.txt or this one less top-output.txt but - unfotunatly they do not work for me... : linux-a9sq:/home/martin # -n 1 > top-output.txt -n: command not found linux-a9sq:/home/martin # top-output.txt If 'top-output.txt' is not a typo you can use command-not-found to lookup the package that contains it, like this: cnf top-output.txt linux-a9sq:/home/martin # top -n 1 -b > top-output.txt linux-a9sq:/home/martin # top -n1 -b | head5 If 'head5' is not a typo you can use command-not-found to lookup the package that contains it, like this: cnf head5 linux-a9sq:/home/martin # what can i do!? love to hear from you greetings
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In the following pages I'm trying to validate if a user is signed in or not. If the user is signed in I would like to see 'Log Out' printed to the screen(I'll do more with that later). If the user is not signed in I would like to see a login form at the top right of the screen. As it stands I'm only seeing 'Log Out' on the screen, I can't get the form to show up anymore. I thought it might be because the session variable was still hanging around but I restarted my computer to make absolutely sure but I'm still just getting 'Log Out'. At the moment I need this program to work as is as much as possible. If you see an entirely different approach that you would use that's fine but I don't currently have the time to go changing a lot, I need to get this going kinda quick. Thanks. records-board.php <?php require_once('includes/init.php'); if(!isset($_SESSION)) { init_session(); } ?> <html> <head> <Title>Pop Report</title> <link rel="stylesheet" type="text/css" href="styles/popreport2.css"> <h1>Pop Report</h1> </head> <body> <?php if(isset($_POST['nameinput']) && isset($_POST['passinput'])) { $nameinput = $_POST['nameinput']; $passinput = $_POST['passinput']; User::sign_in($nameinput, $passinput); } if(!isset($_SESSION['user'])) { print_form(); } else { echo "Log Out "; echo $_SESSION['user']->name; // this line was just trouble shooting, it told me nothing! } ?> user.php <?php if(!isset($_SESSION)) { init_session(); } class User { public $name; public function __construct($username, $password) { $connection = get_db_connection(); $query = $connection->query("SELECT * FROM users WHERE username='$username' AND password='$password'"); if(!$query) { echo "Invalid username or password"; } else { $result = $query->fetch(PDO::FETCH_ASSOC); if(!$result['username'] == $username || !$result['password'] == $password) { echo "Invalid username or password"; } else { $this->name = $result['username']; } } } public static function sign_in($username, $password) { $_SESSION['user'] = new User($username, $password); } } ?> <?php function print_form() { echo "<form id='loginform' name='loginform' action='records-board.php' method='post'>"; echo "Username: <input type='text' name='nameinput'>"; echo "Password: <input type='text' name='passinput'><br />"; echo "<input type='submit' value='Sign In'>"; echo "</form>"; } ?>
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I'm getting the following errors when I run `cat /var/log/apache/error.log` -> PHP Notice: Undefined variable: db_connection in /var/www/html/popreport/includes/inmate.php on line 18 -> PHP Fatal error: Call to a member function query() on a non-object in /var/www/html/popreport/includes/inmate.php on line 18 When I try this in my browser I start with test.php test.php <?php require_once("./database.php"); require_once("./inmate.php"); // foreach($query as $row) // { // print_r($row) . "<br />"; // } $inmate = array(); $inmate = new Inmate($inmate); foreach($inmate as $row) { print $row->firstl_name . "<br />"; } ?> database.php <?php include("./constants.php"); try { $db_connection = new PDO("mysql:host=$host;dbname=$db_name", $db_user, $password); $db_connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch (PDOException $e) { print "Error!: " . $e->getMessage() . "<br />"; die(); } ?> inmate.php <?php require_once("./database.php"); class Inmate { private $first_name = ''; private $last_name = ''; private $full_name = ''; private $race = ''; private $number = 0; private $facility = ''; private $type_of_transit = ''; public function __construct($inmate) { $sql = "SELECT * FROM inmate_board"; $query = $db_connection->query($sql); $result = $query->fetch(PDO::FETCH_ASSOC); foreach($result as $row) { $this->$first_name = $result['first_name']; } } public function get_property($property) { return $this->$property; } } ?> In inmate.php I also tried to change the line `$query = $db_connection->query($sql);` to `$query = global $db_connection->query($sql);` but I didn't have any luck here either. Any ideas?
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[Linux] PHP Notice: Undefined variable: connection in /var/www/html/popreport/functions.php on line 23 PHP Fatal error: Call to a member function query() on a non-object in /var/www/html/popreport/functions.php on line 23 The fuction output in the following program is called from another file called records records-board.php If you look at the program below you'll see that I did define $connection above line 23 in the file functions.php And for the second error I'm really not getting it because that same foreach loop was working fine with the exact same argument list when it was in the file records-board.php, but now that I've copied most of the code from records-board.php and placed it in functions.php all the sudden my program can't see the variable $connection and has a problem with my foreach loop on line 23. Again, both of those lines worked fine when they were in another file. functions.php <?php //session_start(); // open a DB connectiong $dbn = 'mysql:dbname=popcount;host=127.0.0.1'; $user = 'user'; $password = 'password'; try { $connection = new PDO($dbn, $user, $password); } catch (PDOException $e) { echo "Connection failed: " . $e->getMessage(); } $sql = "SELECT full_name, tdoc_number, race, facility FROM inmate_board WHERE type = 'COURT'"; function output() { foreach($connection->query($sql) as $row) { echo "<tr><td>$row[full_name]</td></tr>"; } } ?> records-board.php <? include 'functions.php'; php output(); ?> Any ideas?
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Hi all. I have a script that i want to run in a cronjob. but i dont know why it's not running. i am using godaddy cpanel ps: when i visit the url of the file, it works as expected, and also when i run it via a form button, it works also. what could be the problem? below is the command i used: /usr/local/bin/php -q /home/username/directory/directory/file-name.php thanks
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Hello, There is one php file, the logic is when this code is executing it is getting some data and place in DB, The problem is that when this file I executing from browser, it is working, but when I execute this file from linux shell (as apache user, or root user) like "/usr/bin/php script.php", It is not working, but without any errors. Please advise what I am missing. P.S. Centos8, apache, php 7.4.9
